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gogolik [260]
3 years ago
15

The velocity of a body is increases from 10 m/s ti 15 m/s in 5seconds calculate its acceleration​

Mathematics
2 answers:
11111nata11111 [884]3 years ago
7 0

Answer: acceleration = 1 m/s²

Concept:

Here, we need to know how to calculate the acceleration of a body.

a = Δv / Δt = (v₂ - v₁) / (t₂ - t₁)

v = velocity

t = time

unit = m/s²

Solve:

<u>Given information</u>

v₁ = 10 m/s

v₂ = 15 m/s

Δt = 5 seconds

<u>Given expression</u>

a = (v₂ - v₁) / (t₂ - t₁)

<u>Substitute values into the expression</u>

a = (15 - 10) / 5

<u>Simplify values in parentheses</u>

a = 5 / 5

<u>Simplify by division</u>

\boxed{a=1}

Hope this helps!! :)

Please let me know if you have any questions

larisa [96]3 years ago
3 0

Answer:

accelaration =  \frac{change \: in \: veloity}{time}  \\  =  \frac{15 - 10}{5}  \\  =  \frac{5}{5}  \\  = 1 \frac{m}{ {s}^{ - 2} }

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Maths functions question
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Answer:

a)  OA = 1 unit

b)  OB = 3 units

c)  AB = √10 units

Step-by-step explanation:

<u>Given function</u>:

g(x)=2^x

<h3><u>Part (a)</u></h3>

Point A is the y-intercept of the exponential curve (so when x = 0).

To find the y-value of Point A, substitute x = 0 into the function:

\implies g(0)=2^0=1

Therefore, A (0, 1) so OA = 1 unit.

<h3><u>Part (b)</u></h3>

If BC = 8 units then the y-value of Point C is 8.

The find the x-value of Point C, set the function to 8 and solve for x:

\begin{aligned}f(x) & = 8 \\\implies 2^x & = 8\\2^x & = 2^3\\\implies x &= 3\end{aligned}

Therefore, C (3, 8) so Point B is (3, 0).  Therefore, OB = 3 units.

<h3><u>Part (c)</u></h3>

From parts (a) and (b):

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  • B = (3, 0)

To find the length of AB, use the distance between two points formula:

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

\textsf{where }(x_1,y_1) \textsf{ and }(x_2,y_2)\:\textsf{are the two points.}

Therefore:

\implies \sf AB=\sqrt{(x_B-x_A)^2+(y_B-y_A)^2}

\implies \sf AB=\sqrt{(3-0)^2+(0-1)^2}

\implies \sf AB=\sqrt{(3)^2+(-1)^2}

\implies \sf AB=\sqrt{9+1}

\implies \sf AB=\sqrt{10}\:\:units

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2 years ago
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