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SashulF [63]
3 years ago
7

Q bisects PR, PQ=3y, and PR=42. Find y and QR.

Mathematics
1 answer:
Vedmedyk [2.9K]3 years ago
3 0
|PR| = |PQ| + |QR|; |PQ| = |QR| conclusion |PR| = 2|PQ|

|PQ| = 3y; |PR| = 42; |QR|=?

subtitute

42 = 2(3y)
6y = 42    |divide both sides by 6
y = 7

|QR| = 3(7) = 21
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