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tensa zangetsu [6.8K]
3 years ago
15

43 coins, no nickels, $4.51 equal amount amount of pennies and dimes, how many of each coin

Mathematics
1 answer:
Sonbull [250]3 years ago
3 0
Set up
Let the dimes = d
Let the pennies = p
Let the quarters = q

Equations
You cannot mean that the pennies and dimes have equal numbers. That would mean that each had 21.5 members. Now could you mean that the dime and penny amount could be the same with 43 coins that total 4.00. Four dollars means that you need 40 dimes alone. It must mean that you are including quarters. 

p + d + p = 43          (1)
p = d                        (2)
p +10d +25q = 451  (3)

Note how this last equation = was derived. You have to multiply the dimes by 10 and he quarters by 100 and the total by 100 to get the numbers all in pennies.

Put the results of 2 into 1.
2p  + q = 43                   (4)  
You need to modify equation 3 as well.
p + 10p + 25q = 451
11p + 25q  = 451           (5)

Solve the new equations
2p +  q = 43               (4)
11p + 25q = 451        (5)

Multiply 4 by 25
25(2p- + q = 43)
50p + 25q = 1075     (6)  Subtract (5) from (6)
<u>11p + 25q = 451
</u>39p = 624                        Divide by 39
p = 624 / 39
p = 16

Since the pennies and dimes are equal there are 16 dimes
p + d + q = 43
16 + 16 + q = 43
32 + q = 43
q = 11

Check
16 + 10*16 + 11*25 = ?
16 + 160 + 275  = ?
451 = ?

Nice problem. Thanks for posting.
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Answer:

we have 60 large boxes and 50 small boxes.

Step-by-step explanation:

First, "boxes of two sizes" means we can assign variables:

  Let x = number of large boxes

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Now, "There are 110 boxes in all"    means    x + y = 110

Now, the pounds for each kind of box is:

    (pounds per box)*(number of boxes)

pounds for large boxes     +    pounds for small boxes      =    4200pounds

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Now, Solve for one of the variables in the first equation then replace (substitute) the expression for that variable in the second.  Let's solve for x:

   x = 110 - y          [from eq1]

 

    45(110-y) + 30y = 4200            [from eq2]

     4950 - 45y  + 30y= 4200         [distribute]

     4950 - 15y = 4200

      -15y = -750

         y = 50           [divide both sides by (-15)]

 

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Put that value into either equation (now, which is easier?) to solve for x:

  x = 110 - y

  x = 110 - 50

  x = 60

 There are 60 large boxes.

Now, let's verify our solution:

 

Is   60+50= 110 ?       [eq1]

         110 = 110 ? yes!

Is  60(45) + 50(30) = 4125   ?

     2700 + 1500 = 4200 ?

       4200 = 4200 ? yes

So we have 60 large boxes and 50 small boxes.

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Step-by-step explanation:

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