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SOVA2 [1]
2 years ago
5

Hey circular plot of land has a diameter of 14 yards what is the area of the land use 3.14 for pie

Mathematics
2 answers:
Alexandra [31]2 years ago
6 0
The area of the circular plot of land is 153.86 square yards.

Use this formula:
A = πr^2

Our given is the diameter (14 yards). We will find the radius by dividing it by 2:
14/2 = 7
The radius is 7 yards.

Use formula with given dimensions:
3.14 • 7^2
= 3.14 • 49
= 153.86

Area is measured in square yards, in this case.

FINAL ANSWER (NOT rounded):
153.86 square yards

Hope this helps!
vagabundo [1.1K]2 years ago
3 0

Answer:

153.86 yards²

Step-by-step explanation:

A(Circle) = πr² where r = radius.

r = d/2 where r = radius and d = diameter.

r = 14/2 = 7 yards.

(3.14)(7)² = (3.14)(49) = 153.86 yards²

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Write 95.417 in expanded form with multiplication
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6 0
2 years ago
For students who first enrolled in two year public institutions in a recent​ semester, the proportion who earned a​ bachelor's d
kondaur [170]

Answer:

Null hypothesis =  H_0:p=0.395

Alternate hypothesis =H_a:p>0.395

Step-by-step explanation:

Given : In a recent​ semester, the proportion who earned a​ bachelor's degree within six years was 0.395.

The president of a certain college believes that the proportion of students who enroll in her institution have a higher completion rate.

To Find : Determine the null and alternative hypotheses.

Solution:

In a recent​ semester, the proportion who earned a​ bachelor's degree within six years was<u> 0.395. </u>

Claim : the proportion of students who enroll in her institution <u>have a higher completion rate.</u>

So,null hypothesis =  H_0:p=0.395

Alternate hypothesis =H_a:p>0.395

6 0
2 years ago
What is the perimeter and area of 9ft width and 8ft Long?
Sever21 [200]

Answer:

Perimeter = 34ft Area = 72ft squared

Step-by-step explanation:

The perimeter of an object is all of it's sides combined. Because you stated two values, I assumed your shape is a rectangle. So the perimeter would be:

8 + 8 + 9 + 9 = 34

The area is length times width, so:

8 x 9 = 72

Because it is area, the units are squared.

3 0
3 years ago
J.J.Bean sells a wide variety of outdoor equipment and clothing. The company sells both through mail order and via the internet.
melamori03 [73]

Answer:

99% confidence interval for the true mean difference between the mean amount of mail-order purchases and the mean amount of internet purchases is [$(-31.82) , $12.02].

Step-by-step explanation:

We are given that a random sample of 16 sales receipts for mail-order sales results in a mean sale amount of $74.50 with a standard deviation of $17.25.

A random sample of 9 sales receipts for internet sales results in a mean sale amount of $84.40 with a standard deviation of $21.25.

The pivotal quantity that will be used for constructing 99% confidence interval for true mean difference is given by;

                      P.Q.  =  \frac{(\bar X_1-\bar X_2)-(\mu_1-\mu_2)}{s_p \times \sqrt{\frac{1}{n_1}+\frac{1}{n_2} } }  ~ t__n_1_+_n_2_-_2

where, \bar X_1 = sample mean for mail-order sales = $74.50

\bar X_2 = sample mean for internet sales = $84.40

s_1 = sample standard deviation for mail-order purchases = $17.25

s_2 = sample standard deviation for internet purchases = $21.25

n_1 = sample of sales receipts for mail-order purchases = 16

n_2 = sample of sales receipts for internet purchases = 9

Also,  s_p =\sqrt{\frac{(n_1-1)\times s_1^{2}+(n_2-1)\times s_2^{2} }{n_1+n_2-2} }  =  \sqrt{\frac{(16-1)\times 17.25^{2}+(9-1)\times 21.25^{2} }{16+9-2} } = 18.74

The true mean difference between the mean amount of mail-order purchases and the mean amount of internet purchases is represented by (\mu_1-\mu_2).

Now, 99% confidence interval for (\mu_1-\mu_2) is given by;

             = (\bar X_1-\bar X_2) \pm t_(_\frac{\alpha}{2}_)  \times s_p \times \sqrt{\frac{1}{n_1} +\frac{1}{n_2}}

Here, the critical value of t at 0.5% level of significance and 23 degrees of freedom is given as 2.807.

          = (74.50-84.40) \pm (2.807  \times 18.74 \times \sqrt{\frac{1}{16} +\frac{1}{9}})

          = [$-31.82 , $12.02]

Hence, 99% confidence interval for the true mean difference between the mean amount of mail-order purchases and the mean amount of internet purchases is [$(-31.82) , $12.02].

5 0
3 years ago
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