Answer:
B and E
Step-by-step explanation:
B = - 6, D = - 2, E = 2
d(B, D) = - 2-(-6)= - 2 + 6 = 4 units
d(D, E) 2 - (-2) = 2 + 2 = 4
Since, d( B, D) = d( D, E)
Therefore, Point D is 1/2 of the distance between B and E.
You need to isolate the variables. For the first equation add x to both sides, which leaves you with y.
For the second equation, divide each side by 2 leaving you with
x= 6+y. Subtract y from each side. Subtract x from both sides. Now you have y= x + 6.
Now graph those equations.
<h3>
Answer: angle T = angle W</h3>
Explanation:
We are given the sides are congruent due to the tickmarks. Specifically
TU = WV (single tickmarks)
TV = WX (double tickmarks)
So we just need the "A" of "SAS". The A is between the two S letters, so the angle is between the two sides. For triangle TUV, the angle T is between the two sides with the tickmarks. Similarly, angle W is between the tickmarked sides of triangle WVX.
If we know that angle T = angle W, then we have enough information to use SAS.
One solution
The two (or more) equations would only intersect once
No solution
Lines never intersect
The lines are parallel
Infinite solutions
The lines are the exact same
That’s all the characteristics I know
