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Alla [95]
4 years ago
14

A bank account earns 2.5% interest per year. If the account starts with $500, approximately how many years will it take for the

value of the account to be $750?
Mathematics
1 answer:
belka [17]4 years ago
4 0

Answer:

Step-by-step explanation:

Since we have an amount in the future of 750, we are going to use Future value formula; FV = PV (1+r)^t

where PV= Initial amount deposited

r= interest rate or discount rate

t = total duration of the investment

FV= 750

PV=500

r = 2.5% or 0.025 as a decimal

t = ?

Next, plug in the numbers into the formula;

750 = 500* (1+0.025)^t

divide both sides by 500;

750/500 = 1.025^t

Introduce <em>ln</em> on both sides

ln 1.5 = ln 1.025^{t}

ln 1.5 = t ln 1.025

0.4054651 = 0.0246926 t

Divide both sides by 0.0246926 to solve for t;

0.4054651/0.0246926 = t

t = 16.42

Therefore it will take 16.42 years

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Identify the correct equation that describe the relationship between a sine and cosine wave. a. v(t) = A sin (2πft + π/2) = A co
Flauer [41]

Answer:

A. v(t) = sin (2πft + π/2) = A cos (2πft)

Step-by-step explanation:

According to trigonometry friction, the following relationship are true;

Sin(A+B) = sinAcosB + cosAsinB

We will be using this relationship to check which option is true.

Wave equation is represented as shown;

y(t) = Asin(2πft±theta)

For positive displacement,

y(t) = Asin(2πft+theta)

If theta = π/2

y(t) = Asin(2πft+π/2)

y(t) = A[ sin 2πftcosπ/2 + cos2πft sin π/2]

Since sinπ/2 = 1 and cos (π/2) = 0

y(t) = A[ sin 2πft (0)+ cos2πft (1)]

y(t) = A[0+ cos2πft]

y(t) = Acos2πft

Hence the expression that is true is expressed as;

v(t) = Asin(2πft+π/2) = Acos2πft

8 0
3 years ago
Describe two ways to write equivalent algebraic expressions
Zolol [24]

Answer:

See below.

Step-by-step explanation:

An example would be:

3x^2 + 6

and

3(x^2 + 2) .

The second way is found by dividing the first one by 3).

5 0
3 years ago
Please help me with pythagoras.
lana [24]

Answer:

(q)

cb \:  =  \sqrt{4 {}^{2}  +  {3}^{2} }

cb = 5

q =  \sqrt{ {13}^{2}  -  {5}^{2} }

q = 12

(r)

cb = \sqrt{ {13}^{2} -  {5}^{2}  }

cb = 12

r =  \sqrt{12 {}^{2} - 5 {}^{2}  }

r =  \sqrt{119}

r = 10.91

(s)

ab =  \sqrt{20 {}^{2}  - 16 {}^{2} }

ab = 12

s =  \sqrt{12 {}^{2} + 8 {}^{2}  }

s = 4 \sqrt{13}

s = 14.42

Step-by-step explanation:

8 0
3 years ago
What is the solution to 6x^2 + 2x + 4 = 0?
Angelina_Jolie [31]

Step 1) Divide 6 and 4 (the last 2 numbers) and bring everything else down

<em>6x^24x+2x+4</em>

Step 2) Place in parentheses

<em>(6x^24x)+(2x+4)</em>

Step 3) Figure out what you can take out of each parentheses.

**In the first one, you can take out 6x because both numbers have x and 6 is the largest number 6 and 24 can go into.**

**In the second one, you can only take out 2 because 2 is the largest number that goes into 2 and 4.**

Step 4) You will know you did it correctly when the parentheses match up

<em>6x(x+4) + 2(x+4)</em> <<< this is how it should look

Answer: <em>(6x+2)(x+4)</em>

8 0
3 years ago
Where would we find the point (–10,0)? A). y-axis B).quadrant ll C).x-axis D).quadrant lll
madreJ [45]
C because its not in any quadrant because the Y isn't stated so the point -10,0 is located on the X-axis
4 0
3 years ago
Read 2 more answers
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