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Mekhanik [1.2K]
2 years ago
8

A^2+5A+4 (A=-5). Evaluate the expression

Mathematics
1 answer:
Naddik [55]2 years ago
8 0

Answer:

4

Step-by-step explanation:

First, rewrite the equation with -5 substituted for A:    (-5)^2 +5(-5) +4
Next, simplify that equation:      25 -25 +4
Simplify this further: 4

When A=-5, the solution is 4.

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A rectangle has a length that is 3 more than twice its width. If its area is 152ft^2, what is its perimeter
liberstina [14]

Answer:

Perimeter=54ft^2

Step-by-step explanation:

Let's start by writing what we know in mathematical terms.

A rectangle has a length that is 3 more than twice its width, means:

L-3 = 2W\\L*W = 152

Now all we have to do is solve for one of these values. I'll choose W.

Rewrite the equation:

L = 2W + 3

Input that information into our second equation and solve:

W*(2W + 3) = 152\\2W^2+3W=152\\2W^2+3W-152=0

Find the two W values by factoring the equation (note that the Width can't be negative because you can't have a negative rectangle):

2W^2+3W-152=0\\(2W+19)(W-8)=0\\\\W=-\frac{19}{2}\\W=8

We pick the positive value 8 and plug it into our original equation to find Length:

L = 2W + 3\\L=2(8)+3\\L=19

Finally, after all that, we can use the formula of a perimeter using our newly found Length and Width values (remember not to forget "ft^2" when we get our answer):

2L+2W\\2(19)+2(8)\\Perimeter=54ft^2

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