Answer:
40
Step-by-step explanation:
4 x 2 = 8 x 5
l x w x h
or
Bxh
Answer:
25. If you look at angle B from the first figure you see a square that indicates a 90 degrees angle, thus the figure shown is a right triangle. You can also see that angle C is said to have 60 degrees. a right triangle has a total angle of 180 degrees. so, 180 - 90 - 60 = 30 degrees. Therefore, angle A is 30 degrees.
27. Now you want the measure of the hypotenuse, and you know this a right triangle. so, simply use the law of sines to find the measure of AC :
4cm/sin(60) = AC/Sin90
AC = 4.62 cm
29. angle z is in the other figure and same stuff, just substract the angles, you have 90 degrees and 30 degrees... 180 - 90 - 30 = 60 degrees
31. Angle Y = 90 degrees
this value is already given, it's the little square that indicates a 90 degrees angle.
26. 5 cm
28. 90 degrees
30. You already found AC, use the pythagorean theorem. sqrt((4.62)^2 - 4^2) = 2.31 cm
32. use pythagoras again, square root(5^2 - 3^2) = 4
So as you can see all the measurements are the same because if you see at the very top of your figures it says ABC = XYZ which means pretty much that they have the same values (notice that there is a little something added to the = sign, watch out for that because that's what indicates that two figures are equal in terms of angles and measures.
Answer:
11
Step-by-step explanation:
g(x) = 2x + 7
Put x as 2 and evaluate.
g(2) = 2(2) + 7
Multiply.
g(2) = 4 + 7
Add the terms.
g(2) = 11
No. You can actually solve this question without doing any math. Her only score that is above a 90 is 93, so it will be brought down lower than a 90 very easily by the 77 and the 82.
Answer:
The speed is 20.8 m/s
Step-by-step explanation:
If a projectile ascends vertically, and after 3 seconds it reaches its maximum height, calculate the velocity that it carries to the middle of its downward trajectory
Let the maximum height is h and initial velocity is u.
From first equation of motion
v = u + at
0 = u - g x 3
u = 3 g.....(1)
Use third equation of motion
Let the speed at half the height is v'.
