Answer:
can you explain yourself more please
Your answer is d hope this helps
RHS
=4x-27/0
=not defined=0
LHS
=x-2x+3x+4/7=2x+4/7=(14x+4)/7= 14x+4.
14x=-4
x=-4/14
X=-2/7
Y = x - 28/5. The slope here is 1. A perpendicular line will have a negative reciprocal slope. So our perpendicular line will have a slope of -1.
slope = (y2 - y1) / (x2 - x1)
(k,2)....x1 = k and y1 = 2
(7,0)...x2 = 7 and y2 = 0
sub
slope = (0 - 2) / (7 - k)
slope = -2 / ?......now if we want the slope to be -1..that means the number where the question mark is has to be 2....for that to happen, k has to be 5...because 7 - 5 = 2.
so ur answer is : k = 5
Answer:
a) y = 2x +4
b) y = 1/2x +4
c) y = -2x +11
Step-by-step explanation:
The given equations are in slope-intercept for, so we can read the slope directly from the equation. It is the x-coefficient.
We can then write an equation of a parallel line using the point-slope form of the equation of a line:
y -k = m(x -h) . . . . for a line with slope m through point (h, k)
If you like, you can rearrange this to "slope-intercept" form. Add k and simplify.
y = mx +(k -mh)
__
a) m = 2, (h, k) = (3, 10)
y = 2x +(10 -2·3)
y = 2x +4
__
b) m = 1/2, (h, k) = (0, 4)
y = 1/2x +(4 -(1/2)·0)
y = 1/2x +4
__
c) m = -2, (h, k) = (4, 3)
y = -2x +(3 -(-2)(4))
y = -2x +11
