456 students participated in switch day. The students raised money for charity so that the principal would approve of the day. I
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Answer:
82%
Step-by-step explanation:
We let the random variable X denote the number of defective units in the production run. Therefore, X is normally distributed with a mean of 21 defective units and a standard deviation of 3 defective units.
We are required to find the probability, P(17 < X < 25), that the number of defective units in the production run is between 17 and 25.
This can be carried out easily in stat-crunch;
In stat crunch, click Stat then Calculators and select Normal
In the pop-up window that appears click Between
Input the value of the mean as 21 and that of the standard deviation as 3
Then input the values 17 and 25
click compute
Stat-Crunch returns a probability of approximately 82%
Find the attachment below.
