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vitfil [10]
3 years ago
12

Insert a digit to make numbers divisible by six possible

Mathematics
1 answer:
Kipish [7]3 years ago
5 0

Lets say our number is 237x8

2+3+7+8+x should be divisible by 6.

20+x should be divisible by 6.

x=4

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What would be the critical value for a two-tailed, one-sample t test with 26 degrees of freedom (df = 26) and an alpha level (p
Alika [10]

Answer: The critical value for a two-tailed t-test = 2.056

The critical value for a one-tailed t-test = 1.706

Step-by-step explanation:

Given : Degree of freedom : df= 26

Significance level : \alpha=0.05

Using student's t distribution table , the critical value for a two-tailed t-test will be :-

t_{\alpha/2, df}=t_{0.025,26}=2.056

The critical value for a two-tailed t-test = 2.056

Again, Using student's t distribution table , the critical value for a one-tailed t-test will be :-

t_{\alpha, df}=t_{0.05,26}=1.706

The critical value for a one-tailed t-test = 1.706

6 0
3 years ago
Verify the trigonometric identities
snow_lady [41]
1)

here, we do the left-hand-side

\bf [sin(x)+cos(x)]^2+[sin(x)-cos(x)]^2=2
\\\\\\\
[sin^2(x)+2sin(x)cos(x)+cos^2(x)]\\\\+~ [sin^2(x)-2sin(x)cos(x)+cos^2(x)]
\\\\\\
2sin^2(x)+2cos^2(x)\implies 2[sin^2(x)+cos^2(x)]\implies 2[1]\implies 2

2)

here we also do the left-hand-side

\bf \cfrac{2-cos^2(x)}{sin(x)}=csc(x)+sin(x)
\\\\\\
\cfrac{2-[1-sin^2(x)]}{sin(x)}\implies \cfrac{2-1+sin^2(x)}{sin(x)}\implies \cfrac{1+sin^2(x)}{sin(x)}
\\\\\\
\cfrac{1}{sin(x)}+\cfrac{sin^2(x)}{sin(x)}\implies csc(x)+sin(x)

3)

here, we do the right-hand-side

\bf \cfrac{cos(x)-sin^2(x)}{sin(x)+cos^2(x)}=\cfrac{csc(x)-tan(x)}{sec(x)+cot(x)}
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\cfrac{csc(x)-tan(x)}{sec(x)+cot(x)}\implies \cfrac{\frac{1}{sin(x)}-\frac{sin(x)}{cos(x)}}{\frac{1}{cos(x)}-\frac{cos(x)}{sin(x)}}\implies \cfrac{\frac{cos(x)-sin^2(x)}{sin(x)cos(x)}}{\frac{sin(x)+cos^2(x)}{sin(x)cos(x)}}
\\\\\\
\cfrac{cos(x)-sin^2(x)}{\underline{sin(x)cos(x)}}\cdot \cfrac{\underline{sin(x)cos(x)}}{sin(x)+cos^2(x)}\implies \cfrac{cos(x)-sin^2(x)}{sin(x)+cos^2(x)}
8 0
3 years ago
PLSS HELPP MMEEE FASSTT
marta [7]

Answer:

12313

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
The recursive formula for an arithmetic sequence is an = an - 1 + d.
LekaFEV [45]
If an is a5
and
an-1 is a4

then using your recursive formula for an arithmetic sequence
an=an-1 +d
then
a5=a4+d

now, a4 =6 and common difference "d"  is d=-11
hence
a5=6 -11
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any questions?



3 0
3 years ago
Read 2 more answers
Find m∠ABD and m∠CBD given m∠ABC = 111∘.
sineoko [7]

Answer:

m∠ABD = 88º

m∠CBD = 23º

Step-by-step explanation:

(-10x + 58) + (6x + 41) = 111

Combine like terms

-4x + 99 = 111

Subtract 99 from both sides

-4x = 12

Divide both sides by -4

x = -3

------------------------

m∠ABD = -10x + 58

m∠ABD = -10(-3) + 58

m∠ABD =  = 30 + 58

m∠ABD = 88º

m∠CBD = 6x + 41

m∠CBD = 6(-3) + 41

m∠CBD = -18 + 41

m∠CBD = 23º

7 0
3 years ago
Read 2 more answers
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