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JulijaS [17]
3 years ago
5

Choose the correct correspondence RT​

Mathematics
1 answer:
Marizza181 [45]3 years ago
4 0

<u></u>RT corresponds to TR. correct option b.

<u>Step-by-step explanation:</u>

In the given parallelogram or rectangle , we have a diagonal RT . We need to find which side is in correspondence with side/Diagonal RT of parallelogram URST .

<u>Side TU:</u>

In triangle UTR , we see that TR is hypotenuse and is the longest side among UR & TU . So , TR can never be equal in length to UR & TU . So there's no correspondence of Side TU with RT.

<u>Side TR:</u>

Since, direction of sides are not mentioned here , we can say that TR & RT is parallel & equal to each other . So , TR is in correspondence with side/Diagonal RT of parallelogram URST .

<u>Side UR:</u>

In triangle UTR , we see that TR is hypotenuse and is the longest side among UR & TU . So , TR can never be equal in length to UR & TU . So there's no correspondence of Side UR with RT.

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6 0
2 years ago
If the length of diagonal of a square is 4√2 cm, find it's length, perimeter and area.​
Sonbull [250]

Answer:

As Per Provided Information

  • Length of diagonal of square is 4√2 cm

We have been asked to find the length , perimeter and area of square .

First let's calculate the side of square .

Using Formulae

\boxed{\bf \:Diagonal_{(Square)} \:  = side \sqrt{2}}

On substituting the value in above formula we obtain

\qquad\longrightarrow\sf  \:4 \sqrt{2}  = side \sqrt{2}  \\  \\  \\ \qquad\longrightarrow\sf  \:4  \cancel{\sqrt{2}} = side \cancel{ \sqrt{2}} \\  \\  \\  \qquad\longrightarrow\sf  \:side \:  = 4 \: cm

<u>Therefore</u><u>,</u>

  • <u>Length </u><u>of </u><u>its </u><u>side </u><u>is </u><u>4</u><u> </u><u>cm</u><u>.</u>

Finding the perimeter of square.

\boxed{\bf \: Perimeter_{(Square)} = 4 \times side}

Substituting the value we obtain

\qquad\longrightarrow\sf  \:Perimeter_{(Square)} \:  = 4 \times 4 \\  \\  \\ \qquad\longrightarrow\sf  \:Perimeter_{(Square)} = 16 \: cm

<u>Therefore</u><u>,</u>

  • <u>Perimeter </u><u>of </u><u>square </u><u>is </u><u>1</u><u>6</u><u> </u><u>cm </u><u>.</u>

Finding the area of square .

\boxed{\bf \: Area_{(Square)} =  {side}^{2}}

Substituting the value we get

\qquad\longrightarrow\sf  \:Area_{(Square)} \:  =  {4}^{2}  \\  \\  \\ \qquad\longrightarrow\sf  \:Area_{(Square)} = 16 \:  {cm}^{2}

<u>Therefore</u><u>,</u>

  • <u>Area </u><u>of</u><u> </u><u>square</u><u> </u><u>is </u><u>1</u><u>6</u><u> </u><u>cm²</u><u>.</u>
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