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dsp73
3 years ago
8

What is 2+2-3+9-5+3=

Mathematics
2 answers:
andreev551 [17]3 years ago
7 0

Answer:

8

Step-by-step explanation:

solmaris [256]3 years ago
7 0

Answer: the answer is 8

Step-by-step explanation: hope this helps :)

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At the candy store, a chocolate bar costs c dollars and a vanilla bar costs 2 dollars more than a chocolate bar. Jamie buys a ch
fredd [130]
This is the equation which you can add:
[c + (3(c + 2))] + [5c]


Simplify:
[c + 3c + 6] + [5c] = 9c + 6

And, that's your answer!
4 0
4 years ago
HELP! solve for p p+10/p-7=8/9
Nastasia [14]
\frac{P+10}{P-7} =  \frac{8}{9} 

use the cross method solve the equation.

9P+90=8P-56
9P-8P=-56-90
P=-146

Hope this helps.
8 0
3 years ago
Help will mark brainliest to best answer
ZanzabumX [31]

Answer:

Im not sure but probably its B

4 0
3 years ago
Read 2 more answers
What is the approximate volume of the composite figure? Use 22/7 for pi. Round to the nearest hundredth.
Temka [501]

Answer:

188.57 cm³

Step-by-step explanation:

Half sphere = 1/2 volume sphere

Sphere = 4/3 * 22/7 * 3³

Sphere = 4/3 * 22/7 * 27/1

Sphere = 2376/21 = 113.14

113.14 / 2 = 56.57

Cone = 22/7 * 3² * h/3

Cone = 22/7 * 9/1 * 14/3

Cone = 2772/21 = 132

132 + 56.57 = 188.57 cm³

If my answer is incorrect, pls correct me!

If you like my answer and explanation, mark me as brainliest!

-Chetan K

4 0
3 years ago
Use the equation below to answer the question.
JulijaS [17]

Answer:

The signa notation to represent the first five ten f(x) is given by f(x)=\sum\limits^{5}_{n=1}a_n

Step-by-step explanation:

Given sequence is -5, -9, 13...

Let f(x) be the given sequence and is denoted by

f(x)=\{-5,-9,-13,...\}

Let the first term be a_1, 2^{\textrm{nd}}  term be a_3,...

ie, a_1=-5,a_2=-9, a_3=-13,...

To find the common difference d:

d=a_2-a_1

=-9-(-5)

=-9-(+5)

d=-4

d=a_3-a_2

=-13-(-9)

=-13+9

d=-4

Therefore the common difference d is -4 for given sequence f(x) with a_1=-5 and d=-4, the seqence f(x) is an arithmetic sequence

By defintion of arithmetic sequence

a_n=a+(n-1)d\hfill(1)

Now to find a_4, a_5:

put n=4 in equation (1)

a_4=a+(4-1)d

a_4=-5+(3)(-4)        [since a=-5, d=-4]

=-5-12

a_4=-17

in equation (1)

a_5=a+(5-1)d

a_5=-5+(4)(-4)       [since a=-5, d=-4]

=-5-16

a_5=-21

Therefore a_4=-17 and a_5=-21

Therefore f(x)=\{-5,-9,-13,-17,-21,...\}

Now to represent the sum of the first five terms of f(x) using sigma notation as below

f(x)=\sum_{n=1}^5 a_n

where \sum_{n=1}^5 a_n=a_1+a_2+a_3+a_4+a_5

           -5-9-13-17-21

\sum_{n=1}^5 a_n=-65

4 0
4 years ago
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