SOLUTION
The mean is 4min
standard deviation is 1min
the z score is
where
then we have
The probability the call lasted less than 3 min will be
Therefore, the probability that (z < -1 ) is
[tex]\begin{gathered} Pr(z<-1)=Pr(0
Hence, the percentage of the calls that lasted less than 3 min is 16%
Answer:
Runner-up: $15,000
Winner: $75,000
Step-by-step explanation:
Let's create an equation for this problem.
Let x=the amount the runner-up receives
Let 5x=the amount the winner receives
Then,
x+5x=90,000
6x=90,000
x=15,000
5x=75,000
Here, Equation: 4x + 2y = 4
Divide the equation by 2,
2x + y = 2
y = -2x + 2
Now, compare the equation with y = mx + c
Here, slope (m) = -2
In short, Your Answer would be -2
Hope this helps!
Insert x = 7
so 3/(7+2) - sqr (7-3)
=3 / (9) - sqr (4)
= 1/3 - 2
=1/3 - 6/3
= -5/3
