Answer:yes
Step-by-step explanation:

![\qquad \tt \rightarrow \:Domain = [-9, -1]](https://tex.z-dn.net/?f=%5Cqquad%20%5Ctt%20%5Crightarrow%20%5C%3ADomain%20%3D%20%5B-9%2C%20-1%5D)
![\qquad \tt \rightarrow \:Range = [-1 , 3]](https://tex.z-dn.net/?f=%5Cqquad%20%5Ctt%20%5Crightarrow%20%5C%3ARange%20%3D%20%5B-1%20%2C%203%5D)
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Domain = All possible values of x for which f(x) is defined
[ generally the extension of function in x - direction ]
Range = All possible values of f(x)
[ generally the extension of function in y - direction ]

![\qquad \tt \rightarrow \: domain = [ - 9, -1]](https://tex.z-dn.net/?f=%5Cqquad%20%5Ctt%20%5Crightarrow%20%5C%3A%20domain%20%3D%20%5B%20-%209%2C%20-1%5D)
![\qquad \tt \rightarrow \: range= [ -1,3]](https://tex.z-dn.net/?f=%5Cqquad%20%5Ctt%20%5Crightarrow%20%5C%3A%20range%3D%20%5B%20-1%2C3%5D)
Answered by : ❝ AǫᴜᴀWɪᴢ ❞
Is there any picture we can work with?

- the current possible number of plates
after adding 2 letters into the 1st set:

after adding 2 letters into the 2nd set:

after adding 2 letters into the 3rd set:

after adding 1 letter into the 1st set and 1 into the 2nd set:
after adding 1 letter into the 1st set and 1 into the 3rd set:
after adding 1 letter into the 2nd set and 1 into the 3rd set:
<span>The largest possible number of plates after adding two numbers is 100.
So, </span><span>the largest possible number of additional plates is 100-60=
40</span>
1) 9x + 2 = x + 5 ---> 9x + 2 = 6
subtracted X from one side but not the other
2) 3(x-4) + 5 = 12 ---> 3x + 4 + 5 = 12
didn't distribute correctly: 3(x-4)
multiplied the X by 3 but not the -4