Answer:
2y² + 9
---------------
15y³
Step-by-step explanation:
Start by identifying the LCD, and then change each fraction so that its denominator is the LCD.
Here the LCD is 15y³, which is evenly divisible by 15y and 5y³.
Focus now on the first fraction: 2 / (15y). Multiplying numerator and denominator of this fraction by y² results in
y²·2 2y²
--------- → ----------
y²·15y 15y³ ←This is the correct LCD
Multiplying numerator and denominator of the second fraction by 3 results in:
3·3 9
------------ → ---------
3·5y³ 15y³ ←This is the correct LCD
So now those two original terms look like:
2y² 9
--------- + --------
15y³ 15y³
and this can be written in simpler form as:
2y² + 9
---------------
15y³
Answer:
D. (x-5)^2 = 36
Step-by-step explanation:
If you add 11 to the given equation, you get ...
x^2 -10x = 11
Then you can add the square of half the x-coefficient to complete the square.
x^2 -10x +25 = 11 +25
(x -5)^2 = 36 . . . . simplify to the appropriate form
Answer:
I select b, 1,3, or 9 photos as my answer.
A x = 0
using the law of exponents
= 1
for (6² )^ x = 1 then x = 0
B note that
= 1 ⇒ x = 1
2 → 2^8 × 3^(-5) × 1^(-2) × 3^(-8) × 2^(-12) × 2^(28)
= 2^(8 -12 + 28) × 1 × 3^(- 5 - 8)
= 2^24 × 3^(- 13) = 2^(24)/3^(13) = 10.523 ( 3 dec. places)
Answer:
I will attach the missing drawing with the answer.
9.b)
Plane JKM
Plane JLM
Plane KLM
Step-by-step explanation:
The drawing for this question is missing. I will attach it with the answer.
9.a) Plane JKL is not an appropriate name for the plane because all of three points lie in the same line.
Through a line pass infinite planes. The plane JKL doesn't define a unique plane. That's why plane JKL isn't an appropriate name for the plane.
9.b) We can name the plane using three points that don't lie in the same line.
Three possible names for the plane are :
Plane JKM
Plane JLM
Plane KLM