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3 years ago

Five dollars more than half the price of sweater is equal to 40.39 what is the full price of the sweater

1 answer:

5 0

Define variables:
w = price of a sweater, in dollars
h = price of a shirt, in dollars
2. Set up two equations representing the problem:
w+=+2h+-+5
4h+%2B+3w+=+275
3. Since an equation for one variable is solved, substitute the answer for the variable in the other equation:
4h+%2B+3%282h+-+5%29+=+275
4. Distribute the 3:
4h+%2B+6h+-+15+=+275
5. Combine two terms:
10h+-+15+=+275
6. Add 15 to both sides:
10h+-+15+%2B+15+=+275+%2B+15
7. Cancel and combine terms:
10h+=+290
8. Divide both sides by 10:
%2810h%29%2F10+=+290%2F10
9. Finish simplification:
h+=+29
10. Replace h in your first equation:
w+=+2%2829%29+-+5
11. Solve for w:
w+=+58+-+5
w+=+53
12. Combine your solved equations with your variable definitions for your answer:
A shirt costs $29 and a sweater costs $53.

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The Ferris wheel at the fair requires riders to be over 48 inches

Alona [7]

Answer:

4ft

Step-by-step explanation:

7 0

2 years ago

Find the absolute extrema for f(x,y)=4-x^2-y^4+1/2y^2 over the closed disk D:x^2+y^2 is less than or equal to 1

algol [13]

Find the critical points of $f(x,y)$ :

$\dfrac{\partial f}{\partial x}=-2x=0\implies x=0$

$\dfrac{\partial f}{\partial y}=y-4y^3=y(1-4y^2)=0\implies y=0\text{ or }y=\pm\dfrac12$

All three points lie within $D$ , and $f$ takes on values of

$\begin{cases}f(0,0)=4\\f\left(0,-\frac12\right)=\frac{65}{16}\\f\left(0,\frac12\right)=\frac{65}{16}\end{cases}$

Now check for extrema on the boundary of $D$ . Convert to polar coordinates:

$f(x,y)=f(\cos t,\sin t)=g(t)=4-\cos^2-\sin^4t+\dfrac12\sin^2t=3+\dfrac32\sin^2t-\sin^4t$

Find the critical points of $g(t)$ :

$\dfrac{\mathrm dg}{\mathrm dt}=3\sin t\cos t-4\sin^3t\cos t=\sin t\cos t(3-4\sin^2t)=0$

$\implies\sin t=0\text{ or }\cos t=0\text{ or }\sin t=\pm\dfrac{\sqrt3}2$

$\implies t=n\pi\text{ or }t=\dfrac{(2n+1)\pi}2\text{ or }\pm\dfrac\pi3+2n\pi$

where $n$ is any integer. There are some redundant critical points, so we'll just consider $0\le t< 2\pi$ , which gives

$t=0\text{ or }t=\dfrac\pi3\text{ or }t=\dfrac\pi2\text{ or }t=\pi\text{ or }t=\dfrac{3\pi}2\text{ or }t=\dfrac{5\pi}3$

which gives values of

$\begin{cases}g(0)=3\\g\left(\frac\pi3\right)=\frac{57}{16}\\g\left(\frac\pi2\right)=\frac72\\g(\pi)=3\\g\left(\frac{3\pi}2\right)=\frac72\\g\left(\frac{5\pi}3\right)=\frac{57}{16}\end{cases}$

So altogether, $f(x,y)$ has an absolute maximum of 65/16 at the points (0, -1/2) and (0, 1/2), and an absolute minimum of 3 at (-1, 0).

5 0

3 years ago

Can one of you guys help me please :( thank you

timurjin [86]

Answer:

42???

Step-by-step explanation:

sorry if wrong

hope this helps

5 0

3 years ago

Read 2 more answers

Hi! I have a math question. This is a two part problem.

Mumz [18]

Answer:

Blair chosen to purchase shirt from company B. Given:

Each shirt costs 3.10$

Shipping cost is 4% (0.04) of total order.

=>Total cost without shipping: 150 x 3.10 = 465$

=> Total cost with 4% of shipping: 465 + 465 x 0.04 = 483.6$

=> Total cost Blair paid for one shirt: C = 483.6/150 = 3.22$

The markup is 75% of original cost:

=> Blair can multiply the total cost for one shirt by 0.75

Blair will sell shirt with price which is equal to the sum of total cost for one shirt and markup:

=> P = 3.22 + 3.22 x 0.75 = 5.64$

Hope this helps!

5 0

3 years ago

16) 2 is what percent of 20

KIM [24]

Answer:

2 is 10% of 20.

Step-by-step explanation:

2/20=10.

7 0

3 years ago