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Sever21 [200]
4 years ago
7

I need help with this question... phenobarbital elixir contains 2 grams in 1 liter of elixir. How many milligrams of phenobarbit

al are contained in 1 teaspoon of elixir?
Mathematics
2 answers:
posledela4 years ago
8 0

To solve this problem, all we need is the conversion factor.

We know that there are:

1 liter = 202.884 teaspoons

 

Therefore the mass of Phenobarbital is:

mass = (2 grams / 1 Liter) * (1 teaspoon) * (1 Liter / 202.884 teaspoons)

<span>mass = 0.00986 g = 9.86 x 10^-3 g = 9.86 mg</span>

Bas_tet [7]4 years ago
3 0

Answer:

9.86 milligrams

Step-by-step explanation:

It is given that 1 liter f elixir contains 2 grams of phenobarbital elixir.

Since 202.884 teaspoons = 1 liter

so 1 teaspoon of elixir =  \frac{1}{202.884} liter

∵ 1 liter of elixir contains phenobarbital = 2 gms.

∴  \frac{1}{202.884} liter of elixir contains phenobarbital =  \frac{2*1}{202.884} = 0.009858 grams

or 0.009858 × 10³ milligrams

 = 9.86 milligrams.

Therefore, 9.86 milligrams of phenobarbital will be required.

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A bookstore sold 25 books in 5 days. At this rate
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Answer:

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Step-by-step explanation:

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Please help. Look at screenshot
Citrus2011 [14]

Answer:

a.

<u>Increasing:</u>

x < 0

x > 2

<u>Decreasing:</u>

0 < x < 2

b.

-1 < x < 2

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c.

x < -1

Step-by-step explanation:

a.

Function is increasing when it is going up as we go rightward

Function is decreasing when it is going down as we go rightward

We can see that as we move up (from negative infinity) until x = 0, the function is increasing. Also, as we go right from x = 2 towards positive infinity, the function is going up (increasing).

So,

<u>Increasing:</u>

x < 0

x > 2

The function is going down, or decreasing, at the in-between points of increasing, that is from 0 to 2, so that would be:

<u>Decreasing:</u>

0 < x < 2

b.

When we want where the function is greater than 0, we basically want the intervals at which the function is ABOVE the x-axis [ f(x) > 0 ].

Looking at the graph, it is

from -1 to 2 (x axis)

and 2 to positive infinity

We can write:

-1 < x < 2

x > 2

c.

Now we want when the function is less than 0, that is basically saying when the function is BELOW the x-axis.

This will be the other intervals than the ones we mentioned above in part (b).

Looking at the graph, we see that the graph is below the x-axis when it is less than -1, so we can write:

x < -1

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4 years ago
Q5: The probability that event A occurs is 5/7 and the probability that event B occurs is 2/3 . If A and B are independent event
bekas [8.4K]

Answer:

P(A \cap B)

And we can use the following formula:

P(A \cap B)= P(A)* P(B)

And replacing the info we got:

P(A \cap B) = \frac{5}{7} \frac{2}{3}= \frac{10}{21}=0.476

Step-by-step explanation:

We define two events for this case A and B. And we know the probability for each individual event given by the problem:

p(A) = \frac{5}{7}

p(B) = \frac{2}{3}

And we want to find the probability that A and B both occurs if A and B are independent events, who menas the following conditions:

P(A|B) = P(A)

P(B|A) = P(B)

And for this special case we want to find this probability:

P(A \cap B)

And we can use the following formula:

P(A \cap B)= P(A)* P(B)

And replacing the info we got:

P(A \cap B) = \frac{5}{7} \frac{2}{3}= \frac{10}{21}=0.476

7 0
3 years ago
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