The perimeter of the triangle is: (9.5n - 11.6p - 3.5q) cm.
<h3>What is the Perimeter of a Triangle?</h3>
The total length of all the sides of a triangle is equal to the perimeter of the triangle.
Given a triangle has the following lengths:
- (2.9n-7.8p) centimeters,
- (6.6n-6.4q) centimeters,
- (2.9q-3.8p) centimeters.
The perimeter of the triangle = (2.9n-7.8p) + (6.6n-6.4q) + (2.9q-3.8p)
The perimeter of the triangle = 2.9n - 7.8p + 6.6n - 6.4q + 2.9q - 3.8p
Combine like terms together
The perimeter of the triangle = 2.9n + 6.6n - 7.8p - 3.8p - 6.4q + 2.9q
The perimeter of the triangle = 9.5n - 11.6p - 3.5q
Thus, the perimeter of the triangle is: (9.5n - 11.6p - 3.5q) cm.
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Answer:
Step-by-step explanation:
(4,3)(-6,3)
3-3/-6-4
m=0
y=3
Step-by-step explanation:
How are we supposed to find volume if you don't enter the other elements I.e width, length and height?
But just in case the formulae for finding volume is to multiply is elements. So to find volume multiply is width, length and height.
Answer:
The length of the pool is 28 meters and the width of the pool is 10.5 meters.
Step-by-step explanation:
In the scale drawing of Joe, the community pool has (length : width) = 8 : 3
Let the actual length of the pool is 8x meters and the actual width is 3x meters.
Now, given that the actual pool has a perimeter of 77 meters.
So, 2(8x + 3x) = 77
⇒ 22x = 77
⇒ x = 3.5
So, the length of the pool is 8x = 8(3.5) = 28 meters and the width of the pool is 3x = 3(3.5) = 10.5 meters. (Answer)
Answer:
The slope of the line that contains diagonal OE will be = -3/2
Step-by-step explanation:
We know the slope-intercept form of the line equation
y = mx+b
Where m is the slope and b is the y-intercept
Given the equation of the line that contains diagonal HM is y = 2/3 x + 7
y = 2/3 x + 7
comparing the equation with the slope-intercept form of the line equation
y = mx+b
Thus, slope = m = 2/3
- We know that the diagonals are perpendicular bisectors of each other.
As we have to determine the slope of the line that contains diagonal OE.
As the slope of the line that contains diagonal HM = 2/3
We also know that a line perpendicular to another line contains a slope that is the negative reciprocal of the slope of the other line.
Therefore, the slope of the line that contains diagonal
OE will be = -1/m = -1/(2/3) = -3/2
Hence, the slope of the line that contains diagonal OE will be = -3/2
