Question

HELP!!! ASAP!

Answer 1

The solution to given system of equations is $(x, y) = (\frac{-15}{263} , \frac{-115}{263})$

The given equation has one solution

Solution:

Given system of equations are:

12x - 13y = 5 --------- eqn 1

x = 23y + 10 --------- eqn 2

We have to solve the system of equations by substitution

Substitute eqn 2 in eqn 1

12(23y + 10) - 13y = 5

276y + 120 - 13y = 5

263y = 5 - 120

263y = -115

$y = \frac{-115}{263}$

Substitute the above value of "y" in eqn 2

$x = 23 \times \frac{-115}{263} + 10\\\\x = \frac{-2645}{263} + 10\\\\x = \frac{-2645 + 2630}{263}\\\\x = \frac{-15}{263}$

Thus the solution to given system of equations is $(x, y) = (\frac{-15}{263} , \frac{-115}{263})$

Thus the given equation has one solution