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Airida [17]
3 years ago
14

Determine whether each equation has the given ordered pair as a solution. y = 5x + 8; (0,8)

Mathematics
1 answer:
poizon [28]3 years ago
5 0
(8)=5(0)+8 \\ 8=8
Plug in 8 for y and 0 for x and solve.
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Which quadrant contains the vertex of the following: f(x) =–2x² –8x+11
leonid [27]
Quadrant 2 contains the vertex of f(x)=-2x^2-8x+11
4 0
3 years ago
Which expression is equivalent to 13b+23b−56(b+1)?
ale4655 [162]
Start by combining LIKE-TERMS. 13b AND 23 are LIKE-TERMS because they have the same variable (B) and numbers. Remember PEMDAS OR Please Excuse My Dear Aunt Sally. (Parentheses, Exponents, Multiplication, Division, Addition, Subtraction). There is also FOIL (First, Inside, Outside, Last). Because we will start with Parenthesis(Use the FOIL method because the 56 is part of the parentheses) first, (-56 x b[first part of the set]) = -56b  THEN (-56 x [+ {always carry the sign, this shows that it is positive}]1) = -56

Now we have 13b+23b -56b-56
                     =36b        -56b -56
                     = -20b    - 56
       This is your final equation because THESE ARE NOT LIKE-TERMS, therefore, they CANNOT be combined
7 0
4 years ago
Read 2 more answers
A catering service offers
Fiesta28 [93]

Answer:

There are 52920 ways to do the banquet

Step-by-step explanation:

* Lets revise the combination to solve this problem

- A combination is a collection of the objects where the order

 doesn't matter

- The order is not important in this problem, so we can use the  

  combination nCr to find how many ways can this done

* Lets solve the problem

- A catering service offers 6 appetizers, 7 main courses, 10 desserts.

- A customer is to select 5  appetizers,  4  main courses, 5  desserts

 for a banquet

∵ We want to select  5  appetizers from 6

∴ There are 6C5 ways to chose the appetizers

∵ 6C5 = 6

∴ There are 6 ways to chose the appetizers

∵ We want to select  4  main courses from 7

∴ There are 7C4 ways to chose the main courses

∵ 7C4 = 35

∴ There are 35 ways to chose the main courses

∵ We want to select  5  desserts from 10

∴ There are 10C5 ways to chose the desserts

∵ 10C5 = 252

∴ There are 252 ways to chose the desserts

- To find the number of ways to do the banquet multiply all the

  answers above

∵ The total ways = 6C5 × 7C4 × 10C5

∴ The total ways = 6 × 35 × 252 = 52920

* There are 52920 ways to do the banquet

5 0
3 years ago
Anna wants to factor the polynomial p(x)=5x^4+40x. She knows that the sum of cubes formula is a^3+b^3=(a+b)(a^2−ab+b^2).
Artemon [7]

Answer:

Part A:  Option 2, A: Anna’s answer is incorrect. She correctly factored out 5x, but incorrectly identified a and b, so her answer cannot be correct.

Part B:  Option 3, B: 5x(x+2)(x^2−2x+4)

Step-by-step explanation:

p(x) = 5x^4 + 40x

p(x) = 5x(x^3 + 8)

p(x) = 5x(x + 2)(x^2 - 2x + 4)

Part A:  Option 2, A: Anna’s answer is incorrect. She correctly factored out 5x, but incorrectly identified a and b, so her answer cannot be correct.

Part B:  Option 3, B: 5x(x+2)(x^2−2x+4)

7 0
3 years ago
As a river guide on the gauja river, antra earned $55 per passenger and a $25 tip. if she earned $410 altogether, how many passe
Ket [755]

410 - 25 = 386

385 ÷ 55 = 7 passengers


5 0
3 years ago
Read 2 more answers
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