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sergiy2304 [10]
2 years ago
5

Write an equation in

Mathematics
1 answer:
Nastasia [14]2 years ago
7 0

Answer:

y+6=-3/4(x-2)

Step-by-step explanation:

y-(-6)=-3/4(x-2)

y+6=-3/4(x-2)

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Mr. Jackson has an empty pyramid and an empty prism. The base of the pyramid is congruent to the base of the prism, and their he
IRISSAK [1]
Answer:
Volume of water required to fill the pyramid is rd of the water required to fill the prism completely.
Step-by-step explanation:
Let Mr Jackson has an empty rectangular pyramid and rectangular prism.
Height and base of both are congruent.
So volume of rectangular pyramid

Volume of the rectangular prism = (Area of the base)(height)

[ Since ]


Therefore, amount of water required to fill the pyramid is rd of the water required to fill the prism completely.
8 0
2 years ago
Plss help for a brainlist :)))
sveticcg [70]
Answer:

The slope is 24

Step-by-step explanation:

Use any two points in the graph to find the slope of the graph
- - - - - - - - - - - - - - - - - - - -
Step 1. Use two points

Ex: (10, 320) & (5, 200)

Step 2. Find the slope using the two points

m = slope

m = change in y/change in x

m = (y2 - y1)/(x2 - x1)

m = (200 - 320)/(5 - 10)

m = -120/-5

m = 120/5

m = 24

The slope of the graph/line is 24
5 0
2 years ago
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almond37 [142]

x - √3y - 4 = 0 → <u>Choice</u><u> </u><u>A</u>

Step-by-step explanation:

x - 4 = √3y

x - 4 <u>- √3y</u> = √3y <u>- √3y</u>

x - 4 - √3y = 0

x - √3y - 4 = 0

4 0
3 years ago
Find the measure of one interior angel if a regular 23-gon
Anit [1.1K]

The 23 <em>exterior</em> angles add to 360. The interior angles are supplements of the exterior angles.

180 - 360/23 = 3780 / 23 = 164.3478...

Answer: a

3 0
3 years ago
Consider a nuclear power plant that produces 1200 MW of power and has a conversion efficiency of 34 percent (that is, for each u
Pachacha [2.7K]

Answer:

Fuel used = 111,303,473,760 MJ/year

Step-by-step explanation:

Power production = Fuel energy * Efficiency

1200 MW = Fuel energy * 0.34

Fuel energy = 1200 MW / 0.34 =3529.41 MW

This means it consumes 3529.41 MJ/s.

Per year, it operates 365 days, 24 hours a day, 3600 seconds an hour.

To calculate the fuel used annualy we have to multiplicate by all these factors

Fuel used = 3529.41 MJ/s * 3600 s/hour * 24 hours/day * 365 days/year

Fuel used = 111,303,473,760 MJ/year

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3 years ago
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