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Troyanec [42]
3 years ago
14

Which equation could be used to solve the problem?

Mathematics
1 answer:
m_a_m_a [10]3 years ago
7 0
A. 600/500=pages per day
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These tables of ordered pairs represent some points on the graphs of lines p and r.
Anarel [89]

Answer:

2x-y= -8

2x+y= 7

Step-by-step explanation: hopes this helps :)

4 0
3 years ago
A stand is a frustum shape, formed by removing a small square-based pyramid from the top of
kupik [55]

The frustum can be considered as consisting of a square pyramid, less the

cut volume.

  • The mass of the stand, is approximately 18.60905 kg

Reasons:

The given parameter of the frustum are;

The density of the frustum, ρ = 85 g/cm³

Height of pyramid, h = 9 cm

Side length of base = 10 cm

Height of frustum

By proportional shapes, the side length of the top of the frustum can be found as follows;

\dfrac{4 \, cm}{9 \, cm} = \dfrac{x}{10 \, cm}

x = \dfrac{4 \, cm}{9 \, cm} \times 10 \, cm = 4\frac{4}{9} \, cm

V = \dfrac{h}{3} \times \left(B_1 + B_2 + \sqrt{B_1 \times B_2} \right)

B₁ = 10², B₂ = \left(4\frac{4}{9} \right)^2

Therefore;

V = \dfrac{4}{3} \times \left(10^2 + \left(4\frac{4}{9}  \right)^2  + \sqrt{10^2 \times  \left(4\frac{4}{9}  \right)^2} \right) \approx 218.93

The volume of the stand, V ≈ 218.93 cm³

Mass = Volume × Density

∴ Mass of the stand, m = 218.93 cm³ × 85 g/cm³ = 18,609.05 grams = 18.60905 kg.

Learn more here:

brainly.com/question/24323975

8 0
3 years ago
Students planted 4(2x+3y) amount of trees on saturday and then 3(5x+4) amount of trees on Sunday. What is the total amount of tr
algol [13]
We have to add the amounts:

4(2x+3y) + 3(5x+4)

First, though, we have to distribute:

4*2x + 4*3y + 3*5x + 3*4
8x + 12y + 15x + 12

Now we just need to simplify:

23x + 12y + 12

The  students planted 23x + 12y + 12 trees total.
7 0
4 years ago
What is the slope of the function
yuradex [85]
I’m not sure about the rest but the slope is 4 and the y intercept is 3.
6 0
3 years ago
How would i solve this
Ivahew [28]

#1

\\ \sf\longmapsto f(-3)

\\ \sf\longmapsto -(-3)^2=-9

#2

\\ \sf\longmapsto f(-5)

\\ \sf\longmapsto 5(-5)-2=-25-2=-27

#3

\\ \sf\longmapsto f(-6)=5(-6)-2=-30-2=-32

7 0
3 years ago
Read 2 more answers
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