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There are 50 deer in a particular forest. The population is increasing at a rate of 15% per year. Which exponential growth function represents
the number of deer y in that forest after x months? Round to the nearest thousandth.
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Answer:
The expression that represents the number of deer in the forest is
y(x) = 50*(1.013)^x
Step-by-step explanation:
Assuming that the number of deer is "y" and the number of months is "x", then after the first month the number of deer is:
y(1) = 50*(1+ 0.15/12) = 50*(1.0125) = 50.625
y(2) = y(1)*(1.0125) = y(0)*(1.0125)² =51.258
y(3) = y(2)*(1.0125) = y(0)*(1.0125)³ = 51.898
This keeps going as the time goes on, so we can model this growth with the equation:
y(x) = 50*(1 - 0.15/12)^(x)
y(x) = 50*(1.013)^x
Answer:
Step-by-step explanation:
Actually Welcome to the Concept of the linear equations..
Here given value of x= 5 and y =1 , so we get as,
5a + b = 38 and 5b - a = 8
so, now we multiply equation no. 2 by 5 all over.
==> 25b - 5a = 40....(1)
hence adding new equation and equation no. 1
26b = 78
b = 78/26
hence b = 3 , and a = 7
The answer for the question shown above is the first option: x^2(x^2)^1/4
When you simplify the expression, you obtain the equivalent expression:
(x^10)^1/4
[(x^8)(x2)]^1/4
x^2(x^2)^1/4
Therefore, the asnwer is the option mentioned before.
Here is the final answer
3 2/9
=29/9. Hope it help!
Answer:
90°
Step-by-step explanation:
Through point O draw a ray on left side of O which is || to AB & CD and take any point P on it.
Therefore,
∠ABO + ∠BOP = 180° (by interior angle Postulate)
118° + ∠BOP = 180°
∠BOP = 180° - 118°
∠BOP = 62°.... (1)
Since, ∠BOP + ∠POD = ∠BOD
Therefore, 62° + ∠POD = 152°
∠POD = 152° - 62°
∠POD = 90°.....(2)
∠POD + ∠ODC = 180° (by interior angle Postulate)
90° + ∠ODC = 180°
∠ODC = 180° - 90°
