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Sliva [168]
3 years ago
13

A triangular prism has a height of 9 meters and a triangular base with the following dimensions.

Mathematics
2 answers:
Zarrin [17]3 years ago
6 0
Triangular Prism Area = (2 * triangle area) + prism height * (sum of 3 triangle sides)
(2 * triangle area) = (2 * (1/2) * 6 * 16) =
(2 * triangle area) = (2 * 48)
(2 * triangle area) = 96

Triangular Prism Area = 96 + 9 * (10 + 10 + 16)
Triangular Prism Area = 96 + 9 * 36
Triangular Prism Area = 420 square meters

Source:
http://www.1728.org/triprism.htm


Ann [662]3 years ago
3 0

Answer:

Surface Area of Prism is 420 m².

Step-by-step explanation:

Given: Height of Prism = 9 m

            Length of Sides of Triangle of base = 10 m , 10 m , 16 m

            Height of Triangle in base = 6 m

To find: Surface Area of prism

Surface Area of Prism = 2 × Area of triangle in base + 2 × Area of

                                        rectangle on side 10 m of triangle + Area of

                                        rectangle on side 16 m of triangle.

                                     = 2\times\frac{1}{2}\times base\times height +

                                        2 × length × breadth + length × breadth

                                     = 16\times6 + 2 × 10 × 9 + 16 × 9

                                     = 96 + 180 + 144

                                     = 420 m²

Therefore, Surface Area of Prism is 420 m².

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Answer: Number 1 (a)

a = 22.5 Hence 2a = 45 and 3a = 67.5

Number 1 (b)

b = 244 and c = 26

Number 2 (a)

a = 70 and b = 20

Step-by-step explanation: From the figure in number in number 1(a), we have an isosceles triangle with sides AB and AC being equal in dimensions (as shown by the markings). Therefore angles B and C are also equal (angles subtended by equal sides in an isosceles triangle). If angle B is 3a then angle C equals 3a as well. if the sum of the interior angles of a triangle equals 180, then;

2a+3a+3a = 180

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Divide both sides of the equation by 8

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From the figure shown in number 1(b), we have two isosceles triangles. The first on is ABC with sides AC and BC being of equal length and angles A and B being of equal measurement. The second one is triangle ABD with sides AD and BD being of equal length and angles A and B being of equal measurement. In triangle ABC,

A+B+ 64 = 180 (Sum of the interior angles of a triangle)

A+B = 180 - 64

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Remembering that A and B are of equal measurement, we divide 116 by 2 to arrive at angles A and B

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If angle B equals 58, then in triangle ABD, c is calculated as 58 - 32

Therefore C equals 26.

To calculate angle D (in triangle ABD)

Angle D = 180 - (32+32)

Angle D = 180 - 64

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Therefore to calculate b;

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D + b = 360

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Subtract 116 from both sides of the equation

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A+B+D = 180 (Sum of the interior angles in a triangle)

A+D+40 = 180

Subtract 40 from both sides of the equation

A+D = 140

Remembering that A and D are equal, divide 140 in two

Angle A = 70, and angle D = 70.

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