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Dmitriy789 [7]
3 years ago
15

A restaurant sees about 600 orders on Tuesday. This is down from last Tuesday by about 0.85%. How many did they see last Tuesday

Mathematics
1 answer:
zaharov [31]3 years ago
8 0

Answer:

Number of orders seen on last Tuesday = 605

Step-by-step explanation:

Number of orders seen on Tuesday = 600

It is given that it is 0.85% less than last Tuesday.

Let number of sales on last Tuesday = x

As per question statement:

Number of order on last Tuesday - 0.85% of Number of order on last Tuesday = 600

OR

i.e. if we subtract 0.85% of x from x, it must be equal to 600.

x-\dfrac{0.85}{100}x =600\\\Rightarrow x-\dfrac{0.85}{100}x =600\\\Rightarrow \dfrac{100-0.85}{100}x =600\\\Rightarrow \dfrac{99.15}{100} \times x =600\\\Rightarrow x =\dfrac{600\times 100}{99.15}\\\Rightarrow x =\dfrac{60000}{99.15}\\\Rightarrow x \approx 605

So, there were about 605 order seen last Tuesday.

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The correct options are (1), (3) and (5).

Step-by-step explanation:

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And the distance between the points D' and origin is 3 units.

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2 years ago
At a hockey game a vender sold a combined total of 105 sodas and hot dogs. The number of sodas sold was 39 more than the number
yKpoI14uk [10]

Answer:

<em>Hot dog sold = 33</em>

<em>Sodas Sold = 72</em>

Step-by-step explanation:

<u><em>Given:</em></u>

<em>At a hockey game a vender sold a combined total of 105 sodas and hot dogs. The number of sodas sold was 39 more than the number of hot dogs sold</em>

<u><em>To Find:</em></u>

<em>Number of soda/hot dog sold</em>

<u><em>Solve:</em></u>

<em>h + ( 39 + h ) = 105</em>

<em>h + 39 + h = 105</em>

<em>2h + 39  = 105</em>

<em>h + 19.5 = 52.5</em>

<em>h = 52.5 - 19.5 </em>

<em>This as a system does not use any inequality. "39 more than" means, +39.</em>

<em>h = 33    meaning    d= 72</em>

<em />

<em>Add to check Answer:</em>

<em>33 + 72 = 105</em>

<em>Thus,</em>

<em>Hot dog sold = 33</em>

<em>Sodas Sold = 72</em>

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<u><em>Kavinsky </em></u>

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I NEED HELP PLS i don’t understand exactly how to do this :/
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Answer:

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