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3 years ago

The length of a rectangle is 3 times the width. The area of this rectangle is 243 feet squared.

Mathematics

1 answer:

Natalka [10]3 years ago

6 0

Step-by-step explanation:

width = x

length= 3x

Area = length * width

243=3x * x

3÷243 =3x^2÷3

√81=√x^2

x=9

3x=3*9=27

Width=9

Length=27

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4 years ago

What is the simplified value of the exponential expression 16^1\4

Natalka [10]

If you observe that $16 = 2^4$ , you can rewrite the expression as

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4 years ago

What is the length of the diagonal of a rectangle whose width is 90 cm and whose length is 200 cm? (Round your answer to the nea

Volgvan

Answer: the answer is c.

Step-by-step explanation: Let W, L and D = the width, length and diagonal of the rectangle, respectively.

Then, by the Pythagorean theorem,

W^2 + L^2 = D^2

<=>

D = sqrt(W^2 + L^2)

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None of the choices offers an exact solution. However, an approximate solution is:

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8 0

4 years ago

Find (fog)(2) and (f+g)(2) when f(x) =1/x and g(x) =4x+9

Dahasolnce [82]

$( f o g)(2) = \frac{1}{17}$

$(f + g)(2) = \frac{35}{2}$

Solution:

Given that:

$f(x) = \frac{1}{x}\\\\g(x) = 4x + 9$

To find: (fog)(2) and (f + g)(2)

By composite function,

( f o g)(x) = f (g(x))

Substitute g(x) = 4x + 9 in above formula,

( f o g)(x) = f(4x + 9)

To find (fog)(2) substitute x = 2 in above formula

( f o g)(2) = f(4(2) + 9)

( f o g)(2) = f(8 + 9) = f(17)

We know that $f(x) = \frac{1}{x}$

$( f o g)(2) = f(17) = \frac{1}{17}$

$( f o g)(2) = \frac{1}{17}$

To find (f + g)(2)

We know that,

(f + g)(x) = f (x) + g(x)

Therefore,

(f + g)(2) = f(2) + g(2)

Substitute x = 2 in f(x) and g(x)

$(f + g)(2) = \frac{1}{2} + (4(2) + 9)\\\\(f + g)(2) = \frac{1}{2} + 17 = \frac{1+34}{2} = \frac{35}{2}$

$(f + g)(2) = \frac{35}{2}$

7 0

3 years ago

Help me please thank you!!

levacccp [35]

Answer:

Step-by-step explanation:

Hope this helps and is correct!

7 0

3 years ago

Read 2 more answers