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Romashka [77]
3 years ago
12

Let each square represent 1/3 unit by 1/3 unit

Mathematics
2 answers:
kap26 [50]3 years ago
7 0

Answer:

Step-by-step explanation:

7nadin3 [17]3 years ago
4 0
4110000 is the answer
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The article "Snow Cover and Temperature Relationships in North America and Eurasia"† used statistical techniques to relate the a
poizon [28]

Answer:

Step-by-step explanation:

From the given information,

The ten observation data on october  snow cover for Eurasia  during the years is 6.5, 12.0, 14.9, 10.0, 10.7, 7.9, 21.9, 12.5, 14.5, 9.2

What would you report as a representative, or typical, value of October snow cover for this period, and what prompted your choice?

For the given data, 21.9 is an outlier, so trimmed mean would be good choice for the researcher,

Remove the smallest and the largest values to compute the trimmed mean

\bar x = \frac{12.0+14.9+10.0+10.7+7.9+12.5+14.5+9.2}{8} \\\\=\frac{91.7}{8} \\\\=11.465

6 0
3 years ago
Can someone plz help ASAP this is confusing
mr_godi [17]

Answer:

third option

Step-by-step explanation:

four times a number: 4n

add 8 to it: 4n + 8

All of this equals to -12.

Hence: 4n + 8 = -12

6 0
3 years ago
Read 2 more answers
Joanie is making a map of the trails in the community park . Two of the trails start at the same point and a forty degree angle.
Grace [21]

Answer:

Draw a line on you paper, go to the start of the line and place your Protractor. Look for the 40 degree mark and place a little slash there. Take away the protractor and draw a line going through the slash. (Use a ruler too)

Step-by-step explanation:

For this you need a protractor

6 0
3 years ago
Applying the concepts. Need help finding the value.
luda_lava [24]

we can use formula

log_ab=\frac{ln(b)}{ln(a)}

log_23*log_34*log_45*log_56*log_6 7 *log_7 8=\frac{ln(3)}{ln(2)}*\frac{ln(4)}{ln(3)}*\frac{ln(5)}{ln(4)}*\frac{ln(6)}{ln(5)}*\frac{ln(7)}{ln(6)}*\frac{ln(8)}{ln(7)}

now, we can cancel terms

and then we can simplify it

log_23*log_34*log_45*log_56*log_6 7 *log_7 8=\frac{ln(8)}{ln(2)}

log_23*log_34*log_45*log_56*log_6 7 *log_7 8=\frac{ln(2^3)}{ln(2)}

log_23*log_34*log_45*log_56*log_6 7 *log_7 8=\frac{3ln(2)}{ln(2)}

now, we can simplify it

and we get

log_23*log_34*log_45*log_56*log_6 7 *log_7 8=3...........Answer

5 0
3 years ago
What is the formula of area of quadrilateral
liraira [26]

Answer:

If the diagonal and the length of the perpendiculars from the vertices are given, then the area of the quadrilateral is calculated as:

Area of quadrilateral = (½) × diagonal length × sum of the length of the perpendiculars drawn from the remaining two vertices.

4 0
2 years ago
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