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Lady_Fox [76]
3 years ago
10

Solve the following linear equation and please explain how you did it 6y+8=6(y+4)−16

Mathematics
2 answers:
Tasya [4]3 years ago
6 0

Answer:

infinite solutions, true for all y

Step-by-step explanation:

6y+8=6(y+4)−16

Distribute

6y+8 = 6y+ 24 - 16

Combine like terms

6y+8 = 6y+8

Subtract 6y from each side

8=8

Since this is always true, the equation is true for all real y

solniwko [45]3 years ago
5 0

Answer:

True of all values of 'y'.

Step-by-step explanation:

6y+8=6(y+4)-16\\\\6y+8=6y+24-16\\\\6y+8=6y+8\\\\6y+8-8=6y+8-8\\\\6y=6y\\\\6y-6y=6y-6y\\\\\boxed{0=0}

Hope this helps.

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Vadim26 [7]

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Step-by-step explanation:

Given that:

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6 0
3 years ago
Which system of equations can be used to find the roots of the equation 4x^5-12x^4+6x=5x^3-2x?
Sveta_85 [38]
^{(1)}\ \ 4x^5-12x^4+6x=5x^3-2x\ \ ^{(2)}\\\\  \left\{\begin{array}{ccc}y=4x^5-12x^4+6x\ \ \ ^{(1)}\\y=5x^3-2x\ \ \ ^{(2)}\end{array}\right


Answer: system nr 4.
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3 years ago
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