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3 years ago

Solve the following linear equation and please explain how you did it 6y+8=6(y+4)−16

Mathematics

2 answers:

Tasya [4]3 years ago

6 0

Answer:

infinite solutions, true for all y

Step-by-step explanation:

6y+8=6(y+4)−16

Distribute

6y+8 = 6y+ 24 - 16

Combine like terms

6y+8 = 6y+8

Subtract 6y from each side

8=8

Since this is always true, the equation is true for all real y

solniwko [45]3 years ago

5 0

Answer:

True of all values of 'y'.

Step-by-step explanation:

$6y+8=6(y+4)-16\\\\6y+8=6y+24-16\\\\6y+8=6y+8\\\\6y+8-8=6y+8-8\\\\6y=6y\\\\6y-6y=6y-6y\\\\\boxed{0=0}$

Hope this helps.

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Angelina_Jolie [31]

Use the area of rectangle formula which is:

$\displaystyle \large \tt{A = width \times length}$

Given that:

area of rectangle = 16
width = 8
length = x-5

Substitute in the formula:

$\displaystyle \large{16 = 8 \times (x - 5)} \\ \displaystyle \large{16 = 8(x - 5)}$

Distribute 8 in the expression:

$\displaystyle \large{16 = (8 \times x) + (8 \times ( - 5))} \\ \displaystyle \large{16 = 8x - 40}$

Move -40 to another side and change from -40 to 40.

$\displaystyle \large{16 + 40 = 8x} \\ \displaystyle \large{56= 8x} \\$

Then move 8 to divide 56, leaving only x.

$\displaystyle \large{ \frac{56}{8} = x} \\ \displaystyle \large{7 = x} \\$

Hence, the answer is:

$\displaystyle \large \boxed{x = 7} \\$

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Step-by-step explanation:

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