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Cloud [144]
3 years ago
8

What is the inverse of the function f(x) = 2x + 1? h(x) = one-halfx – one-half

Mathematics
1 answer:
zhuklara [117]3 years ago
3 1

L. amamammamamammanama

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THIS IS 100 POINTS SOMEBODY PLEASEEEEEEEEEEEEEE HELP MEEEEE
Nookie1986 [14]

Answer: Option #4: the 0.2 could be changed to 2.

Explanation:

The table is designed to make the concept of percentages more understandable. The table first allocates the total amount of 70 in terms of its "fifths," or 20% parts. Then it expresses these parts in the last row of the table, showing that 20% of 70 is 14 and all the five parts sum up to 70 again.

Now, Mikel is supposed to express 40% of the amount. So she writes (incorrectly): 0.2 * 14. This statement needs to be changed to 2 * 14 (two times 14 = 28), to correspond to 2 times 20%, or 40%  of 70.

This is reflected in the last (fourth) option "The 0.2 in the expression could be changed to 2."

Option #3 is incorrect because changing 14 to 70, will result in an incorrect number (2.8).

Options 1 and 2 are similarly incorrect (as can be easily verified)

3 0
3 years ago
Read 2 more answers
8. Find all the real fourth roots of 256
mezya [45]
X^4=256
x^4-256=0
(x^2)^2-(16)^2=0
(x^2+16)(x^2-16)=0
either x^2+16=0
it gives complex roots.
or x^2-16=0
or x^2-4^2=0
(x+4)(x-4)=0
either x+4=0,x=-4
or x-4=0
x=4
7 0
3 years ago
Still havent recieved the CORRECT ANSWERS... u will be the brainliest!
yKpoI14uk [10]

Answer: Lol ten points for your whole assignment

Step-by-step explanation:

6 0
3 years ago
U-3/4=4 please help me ty
Ne4ueva [31]
To solve the equation:

\frac{u - 3}{4}  = 4 \\ \frac{u - 3}{4}  \times 4 = 4  \times 4\\ u - 3 = 4 \times 4 \\ u - 3 + 3 = 16 + 3 \\ u = 16 + 3 \\ u = 19

Therefore, the answer is u=19.

Hope it helps!
8 0
3 years ago
Read 2 more answers
Recall what you know about similarity. If circle B is similar to circle A, what must exist?
Arlecino [84]

Answer:

circle a and circle b must exist

Step-by-step explanation:is circle a and circle b did not exist this question would not be one

7 0
2 years ago
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