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Vikki [24]
3 years ago
9

Can someone please answer this math problem and show your working

Mathematics
1 answer:
Jobisdone [24]3 years ago
6 0
X=7 so that means replace all the x values with 7
7^3+5(3)= the answer solve it
7 square 3 + 5 times 3 equal

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Customers arrive at a movie theater at the advertised movie time only to find that they have to sit through several previews and
CaHeK987 [17]

Answer:

57

Step-by-step explanation:

Given that :

Standard deviation (σ) = 5 minutes = (5 *60) = 300 seconds

Margin of Error, E = 78

Assume a confidence interval of 95%;

Using the relation :

((Zα/2 * σ) / E)²

(1 - α)/2 = (1 - 0.95)/2 = 0.05 /2 = 0.025

Z0.025 = 1.96

Sample size = ((1.96 * 300) / 78)²

Sample size = (588 / 78)^2

Sample size = 7.5384615^2

Sample size = 56.828

= 57 samples

5 0
3 years ago
8.902 to the nearest hundredth
k0ka [10]
8.902
     ^this place it the hundreths so if you know how to round it is 8.9 or 8.900
7 0
4 years ago
Please help me with these factoring problems. Please help me solve. I can't do these!!
aleksley [76]
Simple...

you have: 

1.) -8x-16  --->>>

Factor out a -8 -->>

-8(x+2)

2.)9d+15db --->

Factor out 3d -->

3d(3+5b)

3.) 2a-9ax-->>

Factor out -a -->

-1a(9x-2)

Thus, your answer.
3 0
3 years ago
At best buy they have a 42" TV that sells for $1250 and is on sale for 15% off. What
marysya [2.9K]

Answer:

If the television is on sale for 15%, that means that the selling price before tax will be 100 - 15 = 5% of the original price.

1250 * 0.85 = $1062.5 ... this is your selling price BEFORE tax

Now, calculate your tax.

You would pay (1062.5) + (1062.5 * 0.065)  

= 1062.5 + 69.06 (your tax)

= 1131.56 dollars

Step-by-step explanation:

5 0
3 years ago
Solve this system of linear inequalities ( will give brainiest)
lakkis [162]
From the graphs you can see that the graph of the line y= \frac{1}{3} x-3 lies under the graph of the line y= \frac{1}{3} x-1. Then all solutions of unequality y\le \frac{1}{3} x-3 are solutions of unequality y\le \frac{1}{3} x-1, but not all solutions of unequality y\le \frac{1}{3} x-1 are solutions of unequality y\le \frac{1}{3} x-3. 
For example, if x=1, y=-2
-2\le  \frac{1}{3} \cdot 1-1 =- \frac{2}{3} \\ -2\ \textgreater \  \frac{1}{3} \cdot 1-3=- \frac{8}{3}.
Answer: Correct choice is B.



3 0
4 years ago
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