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2 years ago

Markup = original cost × percentage markup

Mathematics

2 answers:

Svetradugi [14.3K]2 years ago

3 0

B) $480

8,000*.06= 480

Flauer [41]2 years ago

3 0

Answer:

B) $480

Step-by-step explanation:

We have been given that a car seller buys a car from a manufacturer for $8,000. He increases the cost by 6 percent. We are asked to find the markup value.

We know that markup is original cost times markup percentage. So markup value for the car would be :

$\text{Mark-up value of car}=\$8,000\times \frac{6}{100}$

$\text{Mark-up value of car}=\$80\times 6$

$\text{Mark-up value of car}=\$480$

Therefore, the mark-up value for the car is $480 and option B is the correct choice.

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muminat

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3 years ago

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Lana71 [14]

Answer:

Step-by-step explanation:

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8 0

2 years ago

Which value is NOT a solution of 8x3 – 1 = 0?

Tpy6a [65]

Note: As you may have unintentionally missed to add the value choices. But, I would make sure to explain the concept so that you may improve your understanding in terms of solving these type of questions.

Answer:

Any value other than the values $x=\frac{1}{2},\:x=-\frac{1}{4}+i\frac{\sqrt{3}}{4},\:x=-\frac{1}{4}-i\frac{\sqrt{3}}{4}$ will not be a solution of $8x^3\:-\:1\:=\:0$ .

Step-by-step explanation:

Considering the equation

$8x^3\:-\:1\:=\:0$

Steps to solve the equation

$8x^3-1=0$

$\mathrm{Add\:}1\mathrm{\:to\:both\:sides}$

$8x^3-1+1=0+1$

$\mathrm{Simplify}$

$x^3=\frac{1}{8}$

$\mathrm{Divide\:both\:sides\:by\:}8$

$\frac{8x^3}{8}=\frac{1}{8}$

$\mathrm{Simplify}$

$x^3=\frac{1}{8}$

$\mathrm{For\:}x^3=f\left(a\right)\mathrm{\:the\:solutions\:are\:}x=\sqrt[3]{f\left(a\right)},\:\sqrt[3]{f\left(a\right)}\frac{-1-\sqrt{3}i}{2},\:\sqrt[3]{f\left(a\right)}\frac{-1+\sqrt{3}i}{2}$

$x=\sqrt[3]{\frac{1}{8}},\:x=\sqrt[3]{\frac{1}{8}}\frac{-1+\sqrt{3}i}{2},\:x=\sqrt[3]{\frac{1}{8}}\frac{-1-\sqrt{3}i}{2}$

So,

$x=\frac{1}{2},\:x=-\frac{1}{4}+i\frac{\sqrt{3}}{4},\:x=-\frac{1}{4}-i\frac{\sqrt{3}}{4}$

Therefore,

Any value other than the values $x=\frac{1}{2},\:x=-\frac{1}{4}+i\frac{\sqrt{3}}{4},\:x=-\frac{1}{4}-i\frac{\sqrt{3}}{4}$ will not be a solution of $8x^3\:-\:1\:=\:0$ .

Keywords: solution, value

Learn more about equation solution from brainly.com/question/1679491

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7 0

2 years ago

Which is the better buy on cookies 98 grams for $5.67 or $127 grams for $7.03 will mark brainiest

Sergio039 [100]

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3 years ago

Read 2 more answers

On the beach boardwalk, there 20 different places to get food. Twenty percent of them are ice cream shops. How many ice cream sh

balu736 [363]

20/100
= 0.2

0.2 x 20
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2 years ago