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2 years ago

12

Can somebody help me with this please

1 answer:

miss Akunina [59]2 years ago

3 0

Answer:

q=-14

Step-by-step explanation:

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7. Are the ordered pairs below an arithmetic sequence or geometric

DochEvi [55]

Answer:

8. Arithmetic Progression

9. $f(9) = 300$

Step-by-step explanation:

Given

$\{(1,55)\ (2, 45)\ (3, 35)\ (4, 25)\}$

Solving (8): Arithmetic or Geometric

We start by checking if it is arithmetic by checking for common difference (d).

$d = y_2 - y_1 = y_3 - y_2 = y_4 - y_3$

This gives:

$d = 45 - 55 = 35 - 45 = 25 - 35$

$d = -10 = -10 = -10$

$d=-10$

<em>Because the common difference is equal, then it is an arithmetic progression</em>

<em></em>

Solving (8):

$f(n) = f(1) + f(n-1)$

To find f(9), we substitute 9 for n

$f(9) = f(1) + f(9-1)$

$f(9) = f(1) + f(8)$

We need to solve for f(8); substitute 8 for n

$f(8) = f(1) + f(8 - 1)$

$f(8) = f(1) + f(7)$

We need to solve for f(7); substitute 7 for n

$f(7) = f(1) + f(7 - 1)$

$f(7) = f(1) + f(6)$

We need to solve for f(6); substitute 6 for n

$f(6) = f(1) + f(6 - 1)$

$f(6) = f(1) + f(5)$

We need to solve for f(5); substitute 6 for n

$f(5) = f(1) + f(5 - 1)$

$f(5) = f(1) + f(4)$

From the function, f(4) = 25 and f(1) = 55.

So:

$f(5)=55 + 25$

$f(5)=80$

$f(6) = f(1) + f(5)$

$f(6) = 55 + 80$

$f(6) = 135$

$f(7) = f(1) + f(6)$

$f(7) = 55 + 135$

$f(7) = 190$

$f(8) = f(1) + f(7)$

$f(8) = 55 + 190$

$f(8) = 245$

$f(9) = f(1) + f(8)$

$f(9) = 55 + 245$

$f(9) = 300$

8 0

2 years ago

Please answer this correctly for a brainliest

m_a_m_a [10]

240. First You divide 420 by 7 then you multiply 60 by 4.

Hope it helped!

4 0

2 years ago

Help me fast please find the area???

goldfiish [28.3K]

1485 this is wrong I think

4 0

2 years ago

Need answer in a simplified fraction 9/20 x 10/9 equals what

Readme [11.4K]

1/2 or 0.5 in decimal form

4 0

2 years ago

Find the area of the figure. Round to the nearest tenth if necessary.

4vir4ik [10]

Answer:

$A=782\ yd^2$

Step-by-step explanation:

The area of the figure is equal to the area of four right triangles

so

The area of one right triangle is equal to

$A=\frac{1}{2}(23)(17)$

$A=195.5\ yd^2$

Multiply by 4

$A=(4)195.5=782\ yd^2$

<em>Alternative Method</em>

The figure is a Rhombus

The area of the Rhombus is equal to

$A=\frac{1}{2}(D_1)(D_2)$

where

D1 and D2 are the diagonals of the rhombus

we have

$D_1=(23+23)=46\ yd\\D_2=(17+17)=34\ yd$

substitute

$A=\frac{1}{2}(46)(34)$

$A=782\ yd^2$

4 0

2 years ago

Read 2 more answers