<h2>
Answer:</h2>
<em><u>Percent value of A with respect to Percent value of B is,</u></em>

<h2>
Step-by-step explanation:</h2>
In the question,
Let us say the value of the Baseball card A and B initially is = 100x
So, for Baseball card A in first 5 years percent increase = 20%
So,
Value after 5 years = 100x + 20% of 100x = 120x
<u>After 5 more years,</u>
Percent decrease = 50%
So,
<u>Value at the end of 10 years = 120x - 50% of 120x = 60x</u>
Now,
For Baseball card B, Percent increase in 10 years = 100%
So,
<u>Value of card B = 100x + 100% of 100x = 200x</u>
So,
<em><u>Percent value of A with respect to Percent value of B is,</u></em>

Answer:
13.98 in²
Step-by-step explanation:
I don't understand it, either.
Point N is part of a "segment" that above and to the right of chord MO. It is the sum of the areas of 3/4 of the circle and a right triangle with 7-inch sides. The larger segment MO to the upper right of chord MO has an area of about 139.95 in², which <u>is not</u> an answer choice.
__
The remaining segment, to the lower left of chord MO does not seem to have anything to do with point N. However, its area is 13.98 in², which <u>is</u> an answer choice. Therefore, we think the question is about this segment, and we wonder why it is called MNO.
The area of a segment is given by the formula ...
A = (1/2)(θ -sin(θ))r² . . . . . . where θ is the central angle in radians.
Here, we have θ = π/2, r = 7 in, so we can compute the area of the smaller segment MO as ...
A = (1/2)(π/2 -sin(π/2))(7 in)² = 24.5(π/2 -1) in² ≈ 13.9845 in²
Rounded to hundredths, this is ...
≈ 13.98 in²
Answer:
The margin of error for the survey is 0.016
Step-by-step explanation:
We are given the following in the question:
Sample size, n = 1024
Sample proportion:

We have to find the margin of error associated with a 90% Confidence interval.
Formula for margin of error:


Putting the values, we get:

Thus, the margin of error for the survey is 0.016
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