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grandymaker [24]
3 years ago
5

Cobalt-60 has a half-life of about 5 years. How many grams of a 300 g sample will remain after 20 years? A: 0.0625 g

Mathematics
2 answers:
aliina [53]3 years ago
8 0

Your question: Cobalt-60 has a half-life of about 5 years. How many grams of a 300 g sample will remain after 20 years?

Answer: <u>C. 18.75g</u>

That's your answer, good luck mate. <u>Remember to always look through notes, so-forth.</u>

Marina86 [1]3 years ago
4 0
The answer is letter c
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1 2/5 = 7/5
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7/5 * 19/5 = 133/25 = 5.32
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Which answer choice contains all the factors of 10
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OK so the factor of 10 is 1 times 10 and 5 times 2
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3 years ago
g European roulette. The game of European roulette involves spinning a wheel with 37 slots: 18 red, 18 black, and 1 green. A bal
butalik [34]

Answer:

The expected value and standard deviation of your total winnings are -$0.081 and $3 respectively.

Step-by-step explanation:

We are given that the game of European roulette involves spinning a wheel with 37 slots: 18 red, 18 black, and 1 green.

Gamblers can place bets on red or black. If the ball lands on their color, they double their money. If it lands on another color, they lose their money.

Let the probability of the ball landing on red slot = \frac{18}{37}

The probability of the ball landing on black slot = \frac{18}{37}

The probability of the ball landing on green slot = \frac{1}{37}

Now, it is stated that Gambler can place bets only on the red or black slot, so;

The probability of winning the bet will be = \frac{18}{37}

and the probability of losing the bet will be = \frac{18}{37}+\frac{1}{37}

                                                                        = \frac{19}{37}

If the gambler wins he gets $3 and if he loses he will get -$3.

So, the expected value of gambler's total winnings is given by;

E(X) = \sum X \times P(X)

        = \$3 \times \frac{18}{37} + (-\$3 \times \frac{19}{37})

        = \$3 \times (-\frac{1}{37})  = -$0.081

Now, the standard deviation of gambler's total winnings is given by;

S.D.(X) = \sqrt{(\sum X^{2}  \times P(X))-(\sum X \times P(X))^{2} }

So, E(X^{2})=\sum X^{2}  \times P(X)

                 = \$3^{2}  \times \frac{18}{37} + (-\$3^{2}  \times \frac{19}{37})

                 = \$9 \times (\frac{18}{37}+\frac{19}{37})  = $9

Now, S.D.(X) = \sqrt{\$9-(-\$0.081)^{2} }

                     = \sqrt{8.993}  = $2.99 ≈ $3

Hence, the expected value and standard deviation of your total winnings are -$0.081 and $3 respectively.

6 0
3 years ago
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Bas_tet [7]

Answer:

Step-by-step explanation:

=3/16

Using Calculator

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8 0
4 years ago
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HELP!
bearhunter [10]
Here is how you would work it out step by step.

You have to factor the equation you're given. (To check you factorization you can "FOIL" it and make sure it matches the original equation)

Then set the two answers you get from FOILing to zero and you should get your answers.

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