Cobalt-60 has a half-life of about 5 years. How many grams of a 300 g sample will remain after 20 years? A: 0.0625 g

mihalych1998 [28]

Answer: slope intercept is y=mx+b form s b= the y intercept and x will just be x and the m is usually a fraction which tells you the slope so what you need to do is mark these points on a line graph draw a line from one to the other and every where it crosses over a point is where you can find the slope and the y intercept giving you the answer

7 0

4 years ago

Prove that the sides opposite the congruent base angles of a triangle are congruent. Be sure to create and name the appropriate

lakkis [162]

Answer:

See explanation

Step-by-step explanation:

Start by dividing the isosceles triangle in half along the upper vertex angle (not the congruent base angles). This creates two right triangles. Since you divide the triangle in half along an angle, they both have an equal base angle, and they share a side, they are congruent by ASA. Since the corresponding sides of congruent triangles are equal, the sides opposite the congruent base angles of a triangle must be congruent.

Hope this helps!

8 0

3 years ago

HELP ASAP IT'S AN EMERGENCY

Lelu [443]

Answer:

AAS

Step-by-step explanation:

Two angles are equivalent and they share a side

4 0

3 years ago

A stool of ribbon holds 6.75 meters.A craft club buys 21 stools. What is the total cost if the ribbon sells for $2 per meter.

OLEGan [10]

283.5

So you multiply 6.75 by 21 stools to find the total number of meters. Then you multiply that by 2.

7 0

4 years ago

The number of events is 29, the number of trials is 298, the claimed population proportion is 0.10, and the significance leve

Nina [5.8K]

Answer:

$z=\frac{0.0973 -0.1}{\sqrt{\frac{0.1(1-0.1)}{298}}}=-0.155$

$p_v =2*P(Z$

And we can use excel to find the p value like this: "=2*NORM.DIST(-0.155;0;1;TRUE)"

So the p value obtained was a very high value and using the significance level given $\alpha=0.05$ we have $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the proportion of interest is not significantly different from 0.1 .

Step-by-step explanation:

1) Data given and notation

n=298 represent the random sample taken

X=29 represent the events claimed

$\hat p=\frac{29}{298}=0.0973$ estimated proportion

$p_o=0.1$ is the value that we want to test

$\alpha=0.05$ represent the significance level

Confidence=95% or 0.95

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

2) Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that the proportion is 0.1 or no.:

Null hypothesis: $p=0.1$

Alternative hypothesis: $p \neq 0.1$

When we conduct a proportion test we need to use the z statistic, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

3) Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.0973 -0.1}{\sqrt{\frac{0.1(1-0.1)}{298}}}=-0.155$

4) Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The next step would be calculate the p value for this test.

Since is a bilateral test the p value would be:

$p_v =2*P(Z$

And we can use excel to find the p value like this: "=2*NORM.DIST(-0.155;0;1;TRUE)"

So the p value obtained was a very high value and using the significance level given $\alpha=0.05$ we have $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the proportion of interest is not significantly different from 0.1 .

We can do the test also in R with the following code:

> prop.test(29,298,p=0.1,alternative = c("two.sided"),conf.level = 1-0.05,correct = FALSE)

7 0

3 years ago