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kolezko [41]
3 years ago
15

The indicated function y1(x) is a solution of the associated homogeneous equation. Use the method of reduction of order to find

a second solution y2(x) of the homogeneous equation and a particular solution yp(x) of the given nonhomogeneous equation. y'' − 7y' + 6y = x; y1 = ex

Mathematics
1 answer:
fenix001 [56]3 years ago
6 0

Answer:

y2 = (6x + 7)/36 + (Dx + E)e^x

Step-by-step explanation:

The method of reduction of order is applicable for second-order differential equations.

For a known solution y1 of a 2nd order differential equation, this method assumes a second solution in the form Uy1 which satisfies the said differential equation. It then assumes a reduced order for U'' (w' = U'').

The differential equation becomes easy to solve, and all that is left are integration and substitutions.

Check attachments for the solution to this problem.

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Answer:

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Step-by-step explanation:

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Solve p(x)= 2x^4-3x^3-6x^2+5x+6
bekas [8.4K]

Answer:

Three solutions were found :

x = 3/2 = 1.500

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Step-by-step explanation:

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3 years ago
Let a,b,,c and x elements in the group G. In each of the following solve for x in terms of a,b,c, and c.
Alchen [17]

Answer with Step-by-step explanation:

We are  given that  a, b, c and x are elements in the group G.

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a.x^2a=bxc^{-1}

x^2ac=bxc^{-1}c=bx

x^{-1}x^2ac=x^{-1}bx=b (x^{-1}bx=b)

xac=b

xacc^{-1}=bc^{-1}

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xaa^{-1}=bc^{-1}a^{-1}

x=bc^{-1}a^{-1}

b.acx=xac

acxc^{-1}=xacc^{-1}=xa  (cc^{-1}=1,cxc^{-1}=x)

axa^{-1}=xaa^{-1}  (aa^{-1}=1,axa^{-1}=x)

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Identity equation

Hence, given equation has infinite solution and satisfied for all values of a and c.

3 0
3 years ago
Endpoint: (-9,-1), midpoint: (8,14) given the midpoint and one endpoint of a line segment, find the other endpoint.
jolli1 [7]

Answer:

 (25, 29)

Step-by-step explanation:

The midpoint formula can be solved to give an expression for one end point of a line segment in terms of the other end point and the midpoint.

<h3>Formula</h3>

The midpoint (M) of segment AB is found from ...

  M = (A +B)/2

Solving for B, we get ...

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<h3>Application</h3>

For A(-9, -1) and M(8, 14), we find the end point B to be ...

  B = 2(8, 14) -(-9, -1)

  B = (16 -(-9), 28 -(-1)) = (25, 29)

The other end point is (25, 29.

7 0
2 years ago
If you place a 29-foot ladder against the top of a building and the bottom of the ladder is 16 feet from the bottom of the build
Anettt [7]

Answer:

24.2 feet.

Step-by-step explanation:

pythagorean theorem will solve this so A^2 + B^2=C^2

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4 0
3 years ago
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