What are the zeros of the function f(x) = x^2 + 5x + 5 written in simplest radical form?

Mathematics

1 answer:

Klio2033 [76]2 years ago

7 0

Answer:

2x = -5 +/- root 5 (opt 3)

Step-by-step explanation:

0 = 4f(x)

= 4(x^2 + 5x + 5)

= 4x^2 + 20x + 20

= (2x)^2 + 2*2x+5 + 25 - 5

= (2x + 5)^2 - (root 5)^2

= ((2x+5) - 5) ((2x + 5) + 5)

= (2x + 5 - 5) (2x + 5 - 5)

Therefore, 2x = -5 +/- root 5

Hope u understand.

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