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Sliva [168]
3 years ago
11

Find two numbers whose sum is 58 and whose difference is 16 Can anyone help me out

Mathematics
1 answer:
White raven [17]3 years ago
7 0
X, y - the numbers

x+y=58 \\
\underline{x-y=16} \\
x+x+y-y=58+16 \\
2x=74 \\
x=37 \\ \\
x+y=58 \\
37+y=58 \\
y=21

The two numbers are 37 and 21.
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Oksi-84 [34.3K]
-2x+ 12 = x^2 +16
-2x -4 = x^2
-4= x^2 + 2x
-4= 3x
-4/3 = 3/3x
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4 0
3 years ago
Marj needs to round $345.67$, and she wants the result to be as large as possible. She has to round to the nearest thousand, the
Andre45 [30]

Answer:

$346.00

Step-by-step explanation:

4 0
2 years ago
The measure (in inches) of the sides of triangle RIO are equivalent to three consecutive odd integers. The perimeter is 201 inch
mariarad [96]
Let 
x-------------> first odd integer
x+2---------> second odd integer
x+4---------> third odd integer

we know that
(x)+(x+2)+(x+4)=201--------> 3x+6=201--------> 3x=195-------> x=65

the three <span>sides of triangle RIO are 
</span>x=65 in
x+2-----> 65+2-----> 67 in
x+4----> 65+4------> 69 in

then
69²=4761----------> c²
(65²+67²)=8714--------> a²+b²
c² < (a²+b²)---------> the triangle RIO is not obtuse
Is acute angle triangle

<span>statements 
1) </span><span>The triangle is obtuse--------> is false
</span>Is acute angle triangle
<span>
2) </span><span>The triangle is scalene-----> is correct
The three sides measures are diferent 

3)</span><span>The smallest side measures 61 inches--------> is false
</span><span>The smallest side measures 65 in
</span><span>
4)</span><span>The largest side measures 69 inches-------> is correct
</span><span>
5) </span><span>If triangle RIO is dilated of 1/3, then the perimeter of the dilated triangle will be 3 units smaller
</span><span>If triangle RIO is dilated of 1/3, then news sides are
</span>65/3------> 21.67 in
67/3-------> 22.33 in
69/3------> 23 in

the new perimeter is=21.67+22.33+23------> 67 in
201-67=134 in
therefore
If triangle RIO is dilated of 1/3, then the perimeter of the dilated triangle will be 3 units smaller----------> is false

Because the perimeter of the dilated triangle will be 134 units smaller

6 0
3 years ago
Read 2 more answers
Lindsay prepared 9 containers of fruit punch for a party. After the party, there were still 4 4/9 containers of fruit punch left
umka2103 [35]

Turn 9 into \frac{81}{9}. Then, convert 4 \frac{4}{9} into a improper faction ( \frac{40}{9} ). Then, subtract

\frac{81}{9} - \frac{40}{9} = \frac{41}{9}. Lastly, convert  \frac{41}{9} to a mixed fraction ( 4\frac{4}{9} ).

Your answer is 4\frac{4}{9}.

6 0
3 years ago
A group of three undergraduate and five graduate students are available to fill certain student government posts. If four studen
creativ13 [48]

Answer:

Pr = 0.4286

Step-by-step explanation:

Given

Let

U \to\\ Undergraduates

G \to Graduates

So, we have:

U = 3; G =5 -- Total students

r = 4 --- students to select

Required

P(U =2)

From the question, we understand that 2 undergraduates are to be selected; This means that 2 graduates are to be selected.

First, we calculate the total possible selection (using combination)

^nC_r = \frac{n!}{(n-r)!r!}

So, we have:

Total = ^{U + G}C_r

Total = ^{3 + 5}C_4

Total = ^8C_4

Total = \frac{8!}{(8-4)!4!}

Total = \frac{8!}{4!4!}

Using a calculator, we have:

Total = 70

The number of ways of selecting 2 from 3 undergraduates is:

U = ^3C_2

U = \frac{3!}{(3-2)!2!}

U = \frac{3!}{1!2!}

U = 3

The number of ways of selecting 2 from 5 graduates is:

G = ^5C_2

G = \frac{5!}{(5-2)!2!}

G = \frac{5!}{3!2!}

G =10

So, the probability is:

Pr = \frac{G * U}{Total}

Pr = \frac{10*3}{70}

Pr = \frac{30}{70}

Pr = 0.4286

5 0
2 years ago
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