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irinina [24]
3 years ago
12

Which statement is true about lines a and b?

Mathematics
2 answers:
Nutka1998 [239]3 years ago
5 0

It would be C. they are skew on ED :)

Maurinko [17]3 years ago
3 0
If they intersect at a 90 degree angle it’s B. If they never intersect if they continued for ever it’s A. If they intersect but it’s not at a 90 degree angle it’s D.
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Anyone please gives me the correct answer to this problem on Khan Academy. The assignment is due tomorrow, and I don't want to f
spin [16.1K]

Answer:

(-2,-2) and (-7,1)

Step-by-step explanation:

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6 0
2 years ago
The CBS’ television show 60 Minutes has been successful for many years. That show recently had a share of 20, which means that a
xxMikexx [17]
Given:
p = 20% = 0.2, sample proportion
n = 5000, sample size.
Confidence level = 95%

The confidence interval is
(p - 1.96k, p + 1.96k)
where
k=\sqrt{ \frac{p(1-p)}{n} }=\sqrt{ \frac{0.2*0.8}{5000}} =0.00566

Therefore the 95% confidence interval is
(0.1943, 0.2057) = (19.4%, 20.6%)

Answer: The 95% confidence interval is (19.4%, 20.6%)
6 0
4 years ago
A coffee packaging plant claims that the mean weight of coffee in its containers is at least 32 ounces. A random sample of 15 co
Luda [366]

Answer:

We conclude that the mean weight of coffee in its containers is at least 32 ounces which means that the data support the claim.

Step-by-step explanation:

We are given that a coffee packaging plant claims that the mean weight of coffee in its containers is at least 32 ounces.

A random sample of 15 containers were weighed and the mean weight was 31.8 ounces with a sample standard deviation of 0.48 ounces.

Let \mu = <u><em>mean weight of coffee in its containers.</em></u>

SO, Null Hypothesis, H_0 : \mu \geq 32 ounces     {means that the mean weight of coffee in its containers is at least 32 ounces}

Alternate Hypothesis, H_A : \mu < 32 ounces      {means that the mean weight of coffee in its containers is less than 32 ounces}

The test statistics that would be used here <u>One-sample t-test statistics</u> as we don't know about population standard deviation;

                             T.S. =  \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample mean weight = 31.8 ounces

             s = sample standard deviation = 0.48 ounces

             n = sample of containers = 15

So, <u><em>the test statistics</em></u>  =  \frac{31.8 -32}{\frac{0.48}{\sqrt{15} } }  ~ t_1_4  

                                      =  -1.614

The value of t test statistics is -1.614.

<u>Now, at 0.01 significance level the t table gives critical value of -2.624 at 14 degree of freedom for left-tailed test.</u>

Since our test statistic is more than the critical value of t as -1.614 > -2.624, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which <u><em>we fail to reject our null hypothesis</em></u>.

Therefore, we conclude that the mean weight of coffee in its containers is at least 32 ounces which means that the data support the claim.

8 0
4 years ago
What is 40.15 divided by 7.3, written as a decimal?
Cloud [144]
The answer is 5.5.
hope this helps!!
5 0
3 years ago
In the diagram below AC is perpendicular to BD find x show all work
ozzi
3x + 9 = 90
3x = 90 - 9 = 81
x = 81/3 = 27
x = 27
7 0
3 years ago
Read 2 more answers
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