- to a point which is more than halfway to the point F. Then draw an arc around the point. Next place the compass point at F and, keeping the same distance between the points of the compass, draw another arc so as to intersect the first arc at 2 points above and below the line EF. Finally draw a line passing through these 2 points of intersection. This is the perpendicular bisector of EF.

3 0

3 years ago

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If r varies directly as w and the constant of variation is 12 what is the value of w when r =42

Airida [17]

r=kw

r=12w

42 = 12*w

divide by 12

42/12 =w

3.5 = w

5 0

3 years ago

Suppose you observe a data point x = 12 and it is known that this data point came from a normal distribution with mean 5 and sta

mihalych1998 [28]

Answer:

The observation would be considered unusual because it is farther than three standard deviations from the mean.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When Z has an absolute value higher than 2, the observation is considered unusual.

In this problem, we have that:

$\mu = 5, \sigma = 2, X = 12$

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{12 - 5}{2}$

$Z = 3.5$

So the correct answer is:

The observation would be considered unusual because it is farther than three standard deviations from the mean.

3 0

4 years ago