Y=25 because 19-2+8 equals 25 so y = 25
Answer:
(a) 
The expected number in the sample that treats hazardous waste on-site is 0.383.
(b) 
There is a 0.000169 probability that 4 of the 10 selected facilities treat hazardous waste on-site.
Step-by-step explanation:
Professional Geographer (Feb. 2000) reported the hazardous waste generation and disposal characteristics of 209 facilities.
N = 209
Only eight of these facilities treated hazardous waste on-site.
r = 8
a. In a random sample of 10 of the 209 facilities, what is the expected number in the sample that treats hazardous waste on-site?
n = 10
The expected number in the sample that treats hazardous waste on-site is given by




Therefore, the expected number in the sample that treats hazardous waste on-site is 0.383.
b. Find the probability that 4 of the 10 selected facilities treat hazardous waste on-site
The probability is given by
For the given case, we have
N = 209
n = 10
r = 8
x = 4




Therefore, there is a 0.000169 probability that 4 of the 10 selected facilities treat hazardous waste on-site.
Answer
Front yard is 20 square root 5 back yard and height is 40 square root 5
Step-by-step explanation:
1. set up A=1/2 H(b1+b2)
2. 6000=1/2 2x (2x+x)
3. 12000=6x^2
4.2000 = x^2
5. x=20 square root 5
Its 0.8333 as percent! Hope that helps! :3
And feel free to pm me if you have anymore questions. ! :3