1) -7(5j + 5) distributive property
2 answers:
You might be interested in
Answer:
Option (4)
Step-by-step explanation:
From the graph attached,
A, B and C are the points based at the heights and valleys of the given curve.
y-coordinates of these points always decide, whether the point is a local maxima or local minima.
y-coordinate of A → -4
y-coordinate of B → 0
y-coordinate of C → -4
Ends of the curve are moving towards infinity, so the absolute maximum is not defined.
Local minimum → -4
Local maximum → 0
Therefore, point representing local maximum is B(0, 0).
Points representing local minimum are A(-2, -4) and C(2, -4).
Option (4) will be the correct option.
9514 1404 393
Answer:
(c) 1.649
Step-by-step explanation:
For a lot of these summation problems it is worthwhile to learn to use a calculator or spreadsheet to do the arithmetic. Here, the ends of the intervals are 1 unit apart, so we only need to evaluate the function for integer values of x.
Almost any of these numerical integration methods involve some sort of weighted sum. For <em>trapezoidal</em> integration, the weights of all of the middle function values are 1. The weights of the first and last function values are 1/2. The weighted sum is multiplied by the interval width, which is 1 for this problem.
The area by trapezoidal integration is about 1.649 square units.
__
In the attached, we have shown the calculation both by computing the area of each trapezoid (f1 does that), and by creating the weighted sum of function values.
