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Fittoniya [83]
3 years ago
15

What is 00000000000004. In scientific notation

Mathematics
1 answer:
never [62]3 years ago
6 0
Your answer is 4.*10^-11
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What is the domain of square root x+6 substract 7
creativ13 [48]
Y=√(x+6) - 7

constraint: x+6> or = 0
or x> 0r = -6
RANGE = x∈R/ x > or = 0
3 0
3 years ago
What is the missing exponent <br> (10^6)^_=10^-18
MaRussiya [10]
Hello, 

You have to know this property:

(x^{a})^b=x^{a*b}\\\\We have:\\\\(10^6)^x=10^{-18}\\\\So:\\ \\ 6*x=-18 \\ x= \frac{-18}{6} \\ \boxed{x=-3}
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3 years ago
Twelve pounds of beans are distributed equally into 8 bags to give out at the food bank. How many pounds of beans are in each ba
BaLLatris [955]
There are 1.5 beans in 1 bag
5 0
3 years ago
A ball is thrown from an initial height of 3 feet with an initial upward velocity of 37 fts. The ball's height h (in feet) after
tatyana61 [14]

Answer:

t=(37+root89)/32,(37-root89)/32

Step-by-step explanation:

Solve the equation:

23=3+37t-16t^2

5 0
3 years ago
A survey reported in Time magazine included the question ‘‘Do you favor a federal law requiring a 15 day waiting period to purch
galben [10]

Answer:

Step-by-step explanation:

Confidence interval for the difference in the two proportions is written as

Difference in sample proportions ± margin of error

Sample proportion, p= x/n

Where x = number of success

n = number of samples

For the men,

x = 318

n1 = 520

p1 = 318/520 = 0.61

For the women

x = 379

n2 = 460

p2 = 379/460 = 0.82

Margin of error = z√[p1(1 - p1)/n1 + p2(1 - p2)/n2]

To determine the z score, we subtract the confidence level from 100% to get α

α = 1 - 0.95 = 0.05

α/2 = 0.05/2 = 0.025

This is the area in each tail. Since we want the area in the middle, it becomes

1 - 0.025 = 0.975

The z score corresponding to the area on the z table is 1.96. Thus, confidence level of 95% is 1.96

Margin of error = 1.96 × √[0.61(1 - 0.61)/520 + 0.82(1 - 0.82)/460]

= 1.96 × √0.0004575 + 0.00032086957)

= 0.055

Confidence interval = 0.61 - 0.82 ± 0.055

= - 0.21 ± 0.055

3 0
3 years ago
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