Answer:
The sum of the other 4 numbers is 
Step-by-step explanation:
Let
x------> the sum of 6 numbers
y-----> the sum of the other 4 numbers
we know that
-----> equation A

substitute the value of x in the equation A






The first thing any good mathematician does is convert the measurements to the same unit as what the question is asking. In this problem, it states that the pool fills at a rate of 20 cubic meters per hour. Just keep in mind that an hour is 60 minutes.
The next step is to see how many cubic meters will cost $300. This can be done by dividing 300 by 10. This gets you 30 cubic meters of water.
You already know that 60 minutes is 20 cubic meters of water. That leaves the remaining 10 cubic meters of water. By dividing the rate given, you get that 30 minutes is 10 cubic meters of water. Add the 60 and 30 together to get 90 minutes.
It will take 90 minutes for the pump to use $300.
Answer:
23,936
Step-by-step explanation:
so get your 17600 times it by 0.36 which gets you 6,336 then add that to 17,600 =23,936
That's how you get your answer
Do you mean 1/2 of 1/4 if so it’s just timsing the numerator by the numerator and the denominator by the denominator. So, 1 x 1 = 1 and 2 x 4 = 8
Therefore it’s 1/8!
If you didn’t understand I’ll gladly elaborate!
<u>Given</u>:
The sides of the base of the triangle are 8, 15 and 17.
The height of the prism is 15 units.
We need to determine the volume of the right triangular prism.
<u>Area of the base of the triangle:</u>
The area of the base of the triangle can be determined using the Heron's formula.

Substituting a = 8, b = 15 and c = 17. Thus, we have;


Using Heron's formula, we have;





Thus, the area of the base of the right triangular prism is 36 square units.
<u>Volume of the right triangular prism:</u>
The volume of the right triangular prism can be determined using the formula,

where
is the area of the base of the prism and h is the height of the prism.
Substituting the values, we have;


Thus, the volume of the right triangular prism is 450 cubic units.