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Colt1911 [192]
2 years ago
9

Help me please ! Also dont be offended if i message back saying why it might be wrong

Mathematics
1 answer:
Drupady [299]2 years ago
6 0

Answer:

1mm = 0.001m \\ 1000mm = 1m \\ 1cm = 0.01m \\ 100cm = 1m \\ 1km = 1000m \\ 0.001km = 1m \\ 1cm = 10mm \\ 0.1cm = 1mm \\  \\ m \:  \: meter \\ cm \:  \: centimeter \\ mm \:  \: millimeter \\ km \:  \: kilometer

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What the slope of(7,3) (6,-2)​
antoniya [11.8K]

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slope =  \frac{ - 2 - 3}{6 - 7}  \\

slope =  \frac{ - 5}{ - 1}  \\

slope = 5

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6 0
3 years ago
Please answer the six questions in the picture please
lisov135 [29]
Y=mx+b
m=slope
b=y itnercept
remember the points go in (x,y) form
also, an easy way to find points is to subsitute values for x andn get values for y

so
6. y=5x-1
 some points are (0,-1) (1,4) (2,9) (314)

7. y=-x+8
some points are (0,8) (1,7) (2,6) (3,5)

8. y=0.2x+.3
somepoints are (0,0.3) (1,0.5) (2,0.7) (3,0.9)

9. y=1.5x-3
somepoints are (0,-3) (1,-1.5) (2,0) (3,1.5)

10. y=-1/2x+4
somepoints are (0,4) (1,7/2) (2,3) (3,5/2)

11. y=2/3x-5
some points are (0,-5) (1,-13/3) (2,-11/3) (3,-3)
6 0
4 years ago
Read 2 more answers
Find all solutions of the given system of equations and check your answer graphically. HINT [See Examples 1-4.] (If there is no
Likurg_2 [28]

Answer:

Infinitely\ many\ solutions\ exist.\\\\Solutions\ are\ (x,\frac{3}{4}x-1)

Step-by-step explanation:

Given\ equations\ are\\\\3x-4y=4.................eq(1)\\\\9x-12y=12..............eq(2)\\\\divide\ eq(2)\ by\ 3\\\\\frac{1}{3}(9x-12y=12)\\\\\Rightarrow 3x-4y=4\\\\Hence\ equations\ represent\ the\ same\ line.\\Hence\ Infinitely\ many\ solutions\ exist.\\\\3x-4y=4\\\\4y=3x-4\\\\y=\frac{3}{4}x-1\\\\Solutions\ are\ (x,\frac{3}{4}x-1)

3 0
3 years ago
What is 2.3e-5 because I don't know what it is.
astraxan [27]
0.000023 i hope that helps
3 0
3 years ago
Two vertices of a right triangle have coordinates (5,12)and(11,12).the segment that connects these ponits is a leg of tje triang
Svetlanka [38]
Both point (5,12) and (11,12) lie on the horizontal line  y=12.

If these two points is a leg of the triangle, the other leg must be perpendicular to the horizontal line, that is, the other leg must be vertical, but passing through either (5,12) or (11,12), i.e. lies on either the vertical line x=5 or x=11.
There is only one point that passes through x=11, i.e. point A(11,4).


8 0
3 years ago
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