Answer: We find out what these numbers have in common for example:
11yd+5yd=16yd so what is 13yd+6yd it is 19yd. This is your answer.
Step-by-step explanation: I hope this helps!
Answer:
here down is the answer
(2y/5y)^3+4y^2+6y
8y^3/125y^3 +16y^2+6y
8/125+16y^2+6y
8/125+16y^2+6y=0
16y^2+6y+8/125=0
it is in the form of quadratic equation
formula :
x=(-b+-square root of b^2-4ac) /2a
here a=16,b=6&c=8/125
x=(-b+-square root of b^2-4ac)/2a
x=(-6+-square root of 36-4.09)/2a here 4.09 came by calculation
x=(-6+-31.91)/2
so
x=(-6+31.91)/2 first (+);
x=25.91/2
x=12.955;
x=(-6-31.91)/2 then(-);
x=-37.91/2
x=-18.955 ;
ans is = 12.955&-18.955;
Answer and Step-by-step explanation: The <u>critical</u> <u>value</u> for a desired confidence level is the distance where you must go above and below the center of distribution to obtain an area of the desired level.
Each sample has a different degree of freedom and critical value.
To determine critical value:
1) Calculate degree of freedom: df = n - 1
2) Subtract the level per 100%;
3) Divide the result by 2 tails;
4) Use calculator or table to find the critical value t*;
For n = 5 Level = 90%:
df = 4
t =
= 0.05
Using t-table:
t* = 2.132
n = 13 Level = 95%:
df = 12
t =
= 0.025
Then:
t* = 2.160
n = 22 Level = 98%
df = 21
t =
= 0.01
t* = 2.819
n = 15 Level = 99%
df = 14
t =
= 0.005
t* = 2.977
The critical values and degree of freedom are:
sample size level df critical value
5 90% 4 2.132
13 95% 12 2.160
22 98% 21 2.819
15 99% 14 2.977
I can not set up a 2 way table online but what they want is a collom of the information neatly laid out...
With the 9th graders in one collom and the 10th graders in the other
like this
9th grader 10th grader
# of students 32 40
# of participated 32 18
Draw this out with lines and it will be correct.
I hope this helps GOOD LUCK...this is tough math for a middle schooler.