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mars1129 [50]
3 years ago
11

What is the equation of a line that has a slope of -2 and goes through (-1, -1)

Mathematics
1 answer:
Sergeeva-Olga [200]3 years ago
5 0

Answer:

y + 11 = - 2(x + 1)

Step-by-step explanation:

The equation of a line in point- slope form is

y - b = m(x - a)

where m is the slope and (a, b) a point on the line

Here m = - 2 and (a, b) = (- 1, - 1), thus

y - (- 1) = - 2(x - (- 1)), that is

y + 1 = - 2(x + 1)

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Urgent help neededddd
Wewaii [24]

Answer:

176

Step-by-step explanation:

V=\frac{1}{3}\times 8 \times 6 \times 11=176 \:cm^3

8 0
2 years ago
Find the Least Common Multiple of these two monomials:
bonufazy [111]

LCM 14 & 24 = 168

then use the highest exponents for the variables

 answer = 168x^6y^6z^8

7 0
3 years ago
What is the gcf of 20 ,12, and 8
xxMikexx [17]
4 is the gif of 20, 12, and 8
6 0
3 years ago
Given JM=27, ml=16, jl=46, nk=15, KLM= 48, JkM=78, MJL=22, find each missing value.
Llana [10]

Answer:

KL = 27

JK = 16

MK = 30

NL = 23

m∠JKL = 132°

m∠KLJ = 22°

m∠KMJ = 54°

m∠KJL = 26°

Step-by-step explanation:

The given parameters of the quadrilateral JKLM are;

JM = 27, ML = 16, JL = 46, NK = 15, KLM = 48, JKM = 78, MJL = 22

Taking the sides as parallel, we have that quadrilateral JKLM is a parallelogram

Therefore;

KL = JM = 27

JK = ML = 16

m∠KLJ = m∠MJL = 22°

MN = NK = 15

MK = MN + NK = 15 + 15 = 30

NL = JL/2 = 46/2 = 23

m∠KJM = m∠KLM = 48°

m∠KJL = m∠KLM - m∠MJL = 48° - 22° = 26°

m∠KML = m∠JKM = 78°

m∠MKL = 180° - m∠KML - m∠KLM = 180° - 78° - 48° = 54°

m∠MKL = 54°

m∠JKL = m∠JKM + m∠MKL = 78° + 54° = 132°

m∠KMJ = m∠MKL = 54°

3 0
2 years ago
Find the sum and express it in the simplest form (-2y-4x+7)+(-4y+x-1)
Marina86 [1]

Y=7+2x......(1)

put this value in 4y+x=1

4(7+2x)+x=1

28+14x+x=1

15x=-27

x=-27/15.....(2)

put this value in eqn (1)

y=7+2(-27/5)

y=7-54/5

y=-3.8

I really hope this helps :D:D:D!!!!

3 0
3 years ago
Read 2 more answers
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