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gavmur [86]
3 years ago
13

The cost of printing a catalog of the products that your company distributes is a flat rate of $52 plus $0.20 per copy. Let C re

present the total cost of printing and x represent the number of copies. Write in symbolic form an equation that will relate C and x. Organize the data into a table of values. Begin with 500 copies, increase by increments of 500, and end with 2500 copies. a. C = 52.20x Number of Copies, x Total Cost, C 500 $52,200 1000 $78,300 1500 $104,400 2000 $130,500 2500 $156,600 c. C = 52 + 0.20x Number of Copies, x Total Cost, C 500 $252 1000 $352 1500 $452 2000 $552 2500 $652 b. C = 52.20x Number of Copies, x Total Cost, C 500 $26,100 1000 $52,200 1500 $78,300 2000 $104,400 2500 $130,500 d. C = 52 + 0.20x Number of Copies, x Total Cost, C 500 $152 1000 $252 1500 $352 2000 $452 2500 $552 Please select the best answer from the choices provided A B C D
Mathematics
2 answers:
Delvig [45]3 years ago
5 0

Answer:

1045384620173418506891046 number of copies

Step-by-step explanation:

10464929103984753671930600 ×55215278300

Nataly_w [17]3 years ago
5 0

Answer:10.4

Step-by-step explanation:

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I need step by step instructions on how to get the y-intercept for the following function:
Svetllana [295]
Luktdkilfdiykfg;oizxkuilouyk7it8rl,kvkuc kugc ulv lug 
4 0
3 years ago
If an experimenter sets equal to .01, then she is defining a "statistically rare" event as an event occurring more than one time
Fynjy0 [20]

Answer:

The correct answer is an event occurring one or fewer times in 100 times if the null hypothesis is true.

Step-by-step explanation:

For a statistically rare event, its probability is relatively small and the event is very unlikely to occur.  Therefore, if an experimental sets equal to 0.01 which is statistically rare, then we can interpret this mathematically as:

p(event) = 0.01 = 1/100

where p(event) is the probability of the event.

In addition, statistically, null hypothesis signifies no major difference between the specified parameters, and any obvious difference that might occur as a result of experimental error. Thus, it can be concluded that the event is occurring one or fewer times in 100 times if the null hypothesis is true.

3 0
3 years ago
Two major automobile manufacturers have produced compact cars with engines of the same size. We are interested in determining wh
Molodets [167]

Answer:

(A) The mean for the differences is 2.0.

(B) The test statistic is 1.617.

(C) At 90% confidence the null hypothesis should not be rejected.

Step-by-step explanation:

We are given that a random sample of eight cars from each manufacturer is selected, and eight drivers are selected to drive each automobile for a specified distance.

The following data (in miles per gallon) show the results of the test;

Driver         Manufacturer A               Manufacturer B

   1                      32                                       28

  2                      27                                       22

  3                      26                                       27

  4                      26                                       24

  5                      25                                       24

  6                      29                                       25

  7                       31                                       28

  8                      25                                       27

Let \mu_1 = mean MPG for the fuel efficiency of Manufacturer A brand

\mu_2 = mean MPG for the fuel efficiency of Manufacturer B brand

SO, Null Hypothesis, H_0 : \mu_1-\mu_2=0  or  \mu_1= \mu_2    {means that there is a not any significant difference in the mean MPG (miles per gallon) when testing for the fuel efficiency of these two brands of automobiles}

Alternate Hypothesis, H_A : \mu_1-\mu_2\neq 0  or  \mu_1\neq  \mu_2   {means that there is a significant difference in the mean MPG (miles per gallon) for the fuel efficiency of these two brands of automobiles}

The test statistics that will be used here is <u>Two-sample t test statistics</u> as we don't know about the population standard deviations;

                      T.S.  = \frac{(\bar X_1-\bar X_2)-(\mu_1-\mu_2)}{s_p\sqrt{\frac{1}{n_1}+\frac{1}{n_2}  } }  ~ t__n__1+_n__2-2

where, \bar X_1 = sample mean MPG for manufacturer A = \frac{\sum X_A}{n_A} = 27.625

\bar X_2 = sample mean MPG for manufacturer B =\frac{\sum X_B}{n_B} = 25.625

s_1 = sample standard deviation for manufacturer A = \sqrt{\frac{\sum (X_A-\bar X_A)^{2} }{n_A-1} } = 2.72

s_2 = sample standard deviation manufacturer B = \sqrt{\frac{\sum (X_B-\bar X_B)^{2} }{n_B-1} } = 2.20

n_1 = sample of cars selected from manufacturer A = 8

n_2 = sample of cars selected from manufacturer B = 8

Also, s_p=\sqrt{\frac{(n_1-1)s_1^{2}+(n_2-1)s_2^{2}  }{n_1+n_2-2} }   =  \sqrt{\frac{(8-1)\times 2.72^{2}+(8-1)\times 2.20^{2}  }{8+8-2} }  = 2.474

(A) The mean for the differences is = 27.625 - 25.625 = 2

(B) <u><em>The test statistics</em></u>  =  \frac{(27.625-25.625)-(0)}{2.474 \times \sqrt{\frac{1}{8}+\frac{1}{8}  } }  ~  t_1_4

                                     =  1.617

(C) Now at 10% significance level, the t table gives critical values between -1.761 and 1.761 at 14 degree of freedom for two-tailed test. Since our test statistics lies within the range of critical values of t, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which <u>we fail to reject our null hypothesis</u>.

Therefore, we conclude that there is a not any significant difference in the mean MPG (miles per gallon) when testing for the fuel efficiency of these two brands of automobiles.

5 0
3 years ago
Which expression is equivalent to 63?<br> а<br> 06x3<br> О 6х6х6<br> я<br> 6х6х6х6<br> O3х3х3х3х3х3
Ne4ueva [31]
None of them? 6x3 is 18, 6x6x6 is 216, 6x6x6x6 is 1296, and 3x3x3x3x3x3 is 729
4 0
3 years ago
A line with a slope of -2/5 that passes through the point (-10,8)
slamgirl [31]

Step-by-step explanation:

m =  -  \frac{2}{3}  \\ ( - 10 ,\: 8) = (x_1,y_1)

y-y_1=m(x-x_1)

Plug in the values into the equation

y - 8 =  -  \frac{2}{3} (x - ( - 10)) \\ y - 8 =  -  \frac{2}{3}( x + 10) \\

y - 8 =  -  \frac{2}{3} x  -  \frac{20}{ 3 }  \\ y =  -  \frac{2}{3} x -  \frac{20}{3}  + 8 \\

y =  -  \frac{2}{3} x +  \frac{4}{3}

To solve for x-intercept , Arrange the values in

ax + by + c = 0

=

-  \frac{2}{3} x - y +  \frac{4}{3}  = 0

To find x-intercept .let y = 0 in the above equation

-  \frac{2}{3} x - y +  \frac{4}{3}  = 0 \\  -  \frac{2}{3} x - 0 +  \frac{4}{3}  = 0 \\

-  \frac{2}{3} x +  \frac{4}{3}  = 0 \\  -  \frac{2}{3} x =  -  \frac{4}{3}

Solve for x ;

x = 2

To find y intercept , let x = 0

and solve for y .

I hope it helps <3

7 0
3 years ago
Read 2 more answers
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