The frequency of the second class is 6.
Since the class width is 6 and the lower limit of the first class is 50, this means the first class goes from 50-55. This would put the second class at 56-61. There are 6 data points in this set that would go in the second class.
Answer:
8 Hours Because 6×8=48 Plus The Cost Was 10$ You Would Just Do 48 + 10 = 58
Step-by-step explanation:
6 × 8 =48 + 10 = 58
Answer:
Each box is 15.99
Step-by-step explanation:
Just the divide the total cost by 6
Answer:
{y,x} = {17/2,-11}
Step-by-step explanation:
Answer:
k(x) + g(x) = x² - 3x + 4
General Formulas and Concepts:
<u>Alg I</u>
Step-by-step explanation:
<u>Step 1: Define</u>
f(x) = 3x - 7
g(x) = 2x² - 3x + 1
h(x) = 4x + 1
k(x) = -x² + 3
<u>Step 2: Find k(x) + g(x)</u>
- Substitute: k(x) + g(x) = -x² + 3 + 2x² - 3x + 1
- Combine like terms (x²): k(x) + g(x) = x² + 3 - 3x + 1
- Combine like terms (Z): k(x) + g(x) = x² - 3x + 4