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Natalija [7]
3 years ago
14

Lisa bought five CDs from the store. The price of each CD was the same. After she bought the CDs,her account balance showed a ch

ange of -$64.95. What would have been the change to Lisa's account balance had she only bought one CD from the store?
Mathematics
2 answers:
Arisa [49]3 years ago
5 0
It would have been at -12.99 so 51.96 less in debt
Advocard [28]3 years ago
5 0

Answer:

$-12.99

Step-by-step explanation:

Lisa bought five CDs from the store at a same price.

After purchasing CDs her account balance showed a deduction of 64.95 = $-64.95

This means the price of 5 CDs = $64.95

The price of one CD =  \frac{64.95}{5}

                                  = $12.99

If she only bought one CD from the store the change to Lisa's account balance showed $-12.99

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The area in square feet, inside a rectangle is given by the expression 1600 x? What is the value
Juli2301 [7.4K]

Answer:1375

Step-by-step explanation:

X= 15 is given

X squared is 15x15 = 225

1600 - 225= 1375

6 0
2 years ago
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Mr. Dewalt suggested contacting a travel agent to see whether they could get a lower price. The agent found a price that was 30%
Dennis_Churaev [7]
First you have to know, that the price the agent found is 70% of  $2075
 (100%-30%=70%)
70%=0,7
$2075 * 0,7 = $1452,5
So 70% 0f $2075 is 1452,5

The price the agant found is $1452,5.
5 0
3 years ago
A psychologist collects data on the time, w, in minutes, people walk each day and their scores, t ,on a stress test. The scores
Svetach [21]
The answer is the last one D that is the correct answer 
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7 0
3 years ago
What are all values of x for which the series shown converges? ​
adoni [48]

Answer:

One convergence criteria that is useful here is that, if aₙ is the n-th term of this sequence, then we must have:

Iaₙ₊₁I < IaₙI

This means that the absolute value of the terms must decrease as n increases.

Then we must have:

\frac{(x -2)^n}{n*3^n} > \frac{(x -2 )^{n+1}}{(n + 1)*3^{n+1}}

We can write this as:

\frac{(x -2)^n}{n*3^n} > \frac{(x -2 )^{n+1}}{(n + 1)*3^{n+1}} = \frac{(x -2)^n}{(n + 1)*3^n} * \frac{(x - 2)}{3}

If we assume that n is a really big number, then:

n + 1 ≈ 1

And we can write:

\frac{(x -2)^n}{n*3^n} > \frac{(x -2)^n}{(n)*3^n} * \frac{(x - 2)}{3}

Then we have the inequality

1 > (x - 2)/3

And remember that this must be in absolute value, then we will have that:

-1 < (x - 2)/3 < 1

-3 < x - 2 < 3

-3 + 2 < x < 3 + 2

-1 < x < 5

The first option looks like this, but it uses the symbols ≤≥, so it is not the same as this, then the correct option will be the second.

5 0
2 years ago
Suppose the mean income of firms in the industry for a year is 95 million dollars with a standard deviation of 5 million dollars
GuDViN [60]

Answer:

Probability that a randomly selected firm will earn less than 100 million dollars is 0.8413.

Step-by-step explanation:

We are given that the mean income of firms in the industry for a year is 95 million dollars with a standard deviation of 5 million dollars. Also, incomes for the industry are distributed normally.

<em>Let X = incomes for the industry</em>

So, X ~ N(\mu=95,\sigma^{2}=5^{2})

Now, the z score probability distribution is given by;

         Z = \frac{X-\mu}{\sigma} ~ N(0,1)

where, \mu = mean income of firms in the industry = 95 million dollars

            \sigma = standard deviation = 5 million dollars

So, probability that a randomly selected firm will earn less than 100 million dollars is given by = P(X < 100 million dollars)

    P(X < 100) = P( \frac{X-\mu}{\sigma} < \frac{100-95}{5} ) = P(Z < 1) = 0.8413   {using z table]

                                                     

Therefore, probability that a randomly selected firm will earn less than 100 million dollars is 0.8413.

5 0
3 years ago
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