60%; Since 1/5 is .2 or 20% and then multiply that by 3.
Answer:
The Probability that the spinner landed on the colors blue and green in any order = 2/9
Step-by-step explanation:
Given - Azul spun a tri-color spinner twice.
To find - What is the probability that the spinner landed on the colors blue and green in any order?
Solution -
Given that,
A tri-color spinner spun twice
So,
The Sample Space, S = {BB, BG, BY, GB, GG, GY, YB, YG, YY}
⇒n(S) = 9
Now,
Let A be an event that the spinner landed on the colors blue and green
So,
A = {BG, GB}
⇒n(A) = 2
Now,
Probability that the spinner landed on the colors blue and green in any order = n(A) ÷ n(S)
= 2 ÷ 9
∴ we get
The Probability that the spinner landed on the colors blue and green in any order = 2/9
Answer:
If its written as the fourth root of (81^3) the answer is 27.
Answer:
The difference in the lengths of the two alligators = 3
Step-by-step explanation:
First, let us make the lengths improper fractions, then we will find the difference from there.
Alligator 1:
Length = 
To convert to improper fraction, multiply the denominator by the whole number, and then add the denominator [(12 × 14) + 5]
Alligator 2:
Length = 
Now Let us find the difference between the lengths:
Therefore the difference in the lengths of the two alligators = 3
We need to see the exercise before that or we cant solve it!
