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2 years ago

What is mean of 8,3,3,7 and 4

1 answer:

3 0

The mean is the average of the numbers. To obtain it, you add all the numbers together and divide by the number of numbers. So:

8+3+3+7+4= 25

25:5= 5

So the answer is: the mean is 5.

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What are the coordinates of the midpoint of the line segment with endpoints B(9,−8) and C(2,−5)?

Temka [501]

So midpoint of segment joining B and C is ( 11/2, - 13/2)

6 0

3 years ago

Whats is the answer to 6×4?

Kazeer [188]

6x4=24

Multiplication is just repeating addition! For example, you can use repetitive (repeating) addition to solve 6x4.

6+6+6+6=24

I added 6 4 times to get to 24. I added it four times because you are multiplying 6 by 4! I am adding 6 (the first number) 4 times (the second number)!

Other examples:

1 x 7=7 because 1+1+1+1+1+1+1=7

2x2=4 because 2+2=4

I hope this helped! :)

6 0

3 years ago

7 = 2g + 5<br><br> pleas help... lolz

Luden [163]

Answer:

2 times 1 = 2 and then plus 5 = 7

Hope this helped (-;

7 0

3 years ago

April worked 1 1/2 times as long on her math project as did Carl. Debbie worked 1 1/4 times as long as Sonia. Richard worked 1 3

vlada-n [284]

Answer:

Student Hours worked

April. $7\frac{7}{8} \ hrs$

Debbie. $8\frac{1}{8}\ hrs$

Richard. $7\frac{19}{24}\ hrs$

Step-by-step explanation:

Some data's were missing so we have attached the complete information in the attachment.

Given:

Number of Hours Carl worked on Math project = $5\frac{1}{4}\ hrs$

$5\frac{1}{4}\ hrs$ can be Rewritten as $\frac{21}{4}\ hrs$

Number of Hours Carl worked on Math project = $\frac{21}{4}\ hrs$

Number of Hours Sonia worked on Math project = $6\frac{1}{2}\ hrs$

$6\frac{1}{2}\ hrs$ can be rewritten as $\frac{13}{2}\ hrs$

Number of Hours Sonia worked on Math project = $\frac{13}{2}\ hrs$

Number of Hours Tony worked on Math project = $5\frac{2}{3}\ hrs$

$5\frac{2}{3}\ hrs$ can be rewritten as $\frac{17}{3}\ hrs.$

Number of Hours Tony worked on Math project = $\frac{17}{3}\ hrs.$

Now Given:

April worked $1\frac{1}{2}$ times as long on her math project as did Carl.

$1\frac{1}{2}$ can be Rewritten as $\frac{3}{2}$

Number of Hours April worked on math project = $\frac{3}{2}$ $\times$ Number of Hours Carl worked on Math project

Number of Hours April worked on math project = $\frac{3}{2}\times \frac{21}{4} = \frac{63}{8}\ hrs \ \ Or \ \ 7\frac{7}{8} \ hrs$

Also Given:

Debbie worked $1\frac{1}{4}$ times as long as Sonia.

$1\frac{1}{4}$ can be Rewritten as $\frac{5}{4}$ .

Number of Hours Debbie worked on math project = $\frac{5}{4}$ $\times$ Number of Hours Sonia worked on Math project

Number of Hours Debbie worked on math project = $\frac{5}{4}\times \frac{13}{2}= \frac{65}{8}\ hrs \ \ Or \ \ 8\frac{1}{8}\ hrs$

Also Given:

Richard worked $1\frac{3}{8}$ times as long as tony.

$1\frac{3}{8}$ can be Rewritten as $\frac{11}{8}$

Number of Hours Richard worked on math project = $\frac{11}{8}$ $\times$ Number of Hours Tony worked on Math project

Number of Hours Debbie worked on math project = $\frac{11}{8}\times \frac{17}{3}= \frac{187}{24}\ hrs \ \ Or \ \ 7\frac{19}{24}\ hrs$

Hence We will match each student with number of hours she worked.

Student Hours worked

April. $7\frac{7}{8} \ hrs$

Debbie. $8\frac{1}{8}\ hrs$

Richard. $7\frac{19}{24}\ hrs$

5 0

3 years ago

Read 2 more answers

Seven times the sum of a number 9 and 2 equals .

zmey [24]

I think it’s 9+2 because it say sum

8 0

2 years ago

Read 2 more answers