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yarga [219]
2 years ago
6

A piece of land is shaped like a right triangle. Two people start at the right angle of the triangle at the same​ time, and walk

at the same speed along different legs of the triangle. If the area formed by the positions of the two people and their starting point​ (the right​ angle) is changing at 2 m squared divided by a comma then how fast are the people moving when they are 3 m from the right​ angle

Mathematics
1 answer:
Oduvanchick [21]2 years ago
6 0

Answer:

They are moving at a speed of 2/3 meters per second.

Step-by-step explanation:

The field is shown in the attached figure below

As we can see that ant any instant of time Area of the triangle is given by

A=\frac{1}{2}x\times x\\\\A=\frac{1}{2}x^2

Differentiating both sides of the above equation with respect to time we get

\frac{dA}{dt}=\frac{1}{2}\cdot \frac{dx^2}{dt}\\\\\frac{dA}{dt}=\frac{1}{2}\cdot 2x\cdot \frac{dx}{dt}\\\\\frac{dA}{dt}=x\cdot v

Applying values in the given relation we get

v=\frac{A'}{x}=\frac{2}{3}=\frac{2}{3}m/s

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4 0
3 years ago
Anyone? i dont understand
Murljashka [212]

Answer:

1725ft^2

Step-by-step explanation:

Hi!

First you have to find your two bases B1 and B2, which are 50 and 65.

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I hope this helps!

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HELP ME PLEASE!
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