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Sergio039 [100]

3 years ago

14

The expression \[\sqrt[4]{16x^2y^7}\] is equivalent to

1 answer:

slava [35]3 years ago

8 0

The solution to the problem is as follows:

<span>4 sqrt(16x^2 y^7)

Protip: sqrt(abc) = sqrt(a)sqrt(b)sqrt(c). Therefore,

4sqrt(16x^2y^7) = 4sqrt(16)sqrt(x^2)sqrt(y^7)

We can deal with sqrt(16); it is equal to 4.

4(4) sqrt(x^2)sqrt(y^7)
16sqrt(x^2)sqrt(y^7)

Next, it is a known fact that sqrt(z^2) is the same as |z|, or the absolute value of z. That means
sqrt(x^2) = |x|

16|x| sqrt(y^7)

Split y^7 as y^6 * y

16|x| sqrt(y^6 * y)
16|x| sqrt(y^6) sqrt(y)
16|x| sqrt([y^3]^2) sqrt(y)
16|x| |y^3| sqrt(y)
</span>
I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!

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Karo-lina-s [1.5K]

$▪▪▪▪▪▪▪▪▪▪▪▪▪ {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪$

Base of a cube is a square, and in the given figure it's stated that the measure of each side is " x " ft

Therefore it's Area is equal to : -

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$x \times x$

${x}^{2}$

Now, since it's Area is given as 1/4 ft², let's equate the Areas to find the measure of each side ~

that is ~

${x}^{2} = \dfrac{1}{4}$

$x = \sqrt{ \dfrac{1}{2} \times \dfrac{1}{2} }$

$x = \dfrac{1}{2} \: \: feet$

It's time to find the volume of cube that is ~

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So, let's plug the value of side length (1/2 ft)

Volume is equal to ~

${ \bigg(\dfrac{1}{2} \bigg) }^{3}$

$\dfrac{1}{8} \: \: ft {}^{3}$

Hence, the required 1/8 or 0.125 ft³

I hope it helped ~

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3 0

3 years ago

Read 2 more answers

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kifflom [539]

Answer:

$\displaystyle y=\frac{2}{3}(x+5)+2$

Step-by-step explanation:

We need to find the equation of the line perpendicular to the line 3x+2y=8 and passes through (-5,2).

The given line can be expressed as:

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We can see the slope of this line is m1=-3/2.

The slopes of two perpendicular lines, say m1 and m2, meet the condition:

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Solving for m2:

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$\displaystyle m_2=-\frac{1}{-\frac{3}{2}}$

$\displaystyle m_2=\frac{2}{3}$

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$y=m(x-h)+k$

Where m is the slope and (h,k) is the point. Using the provided point (-5,2):

$\boxed{\displaystyle y=\frac{2}{3}(x+5)+2}$

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