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Sergio039 [100]
3 years ago
14

The expression \[\sqrt[4]{16x^2y^7}\] is equivalent to

Mathematics
1 answer:
slava [35]3 years ago
8 0
The solution to the problem is as follows:

<span>4 sqrt(16x^2 y^7) 

Protip: sqrt(abc) = sqrt(a)sqrt(b)sqrt(c). Therefore, 

4sqrt(16x^2y^7) = 4sqrt(16)sqrt(x^2)sqrt(y^7) 

We can deal with sqrt(16); it is equal to 4. 

4(4) sqrt(x^2)sqrt(y^7) 
16sqrt(x^2)sqrt(y^7) 

Next, it is a known fact that sqrt(z^2) is the same as |z|, or the absolute value of z. That means 
sqrt(x^2) = |x| 

16|x| sqrt(y^7) 

Split y^7 as y^6 * y 

16|x| sqrt(y^6 * y) 
16|x| sqrt(y^6) sqrt(y) 
16|x| sqrt([y^3]^2) sqrt(y) 
16|x| |y^3| sqrt(y)
</span>
I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
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A plane flying overhead at night is located by two
Gemiola [76]

Answer:

Step-by-step explanation:

B

2

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Let the distance of two consecutive stones are x, x+1.

In ΔBCD, we have

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⇒x=

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      .....(i)

In ΔABC, we have

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 km

solution

6 0
3 years ago
PLZ HELP ME. IF YOU HAVE ANY QUESTIONS MESSAGE ME!!
sdas [7]
I'm sure it's B
hope this helps :)
5 0
4 years ago
How to you solve x2 -20x -17 = -53
Gennadij [26K]

Answer:

solve for x

x=2

Step-by-step explanation:

x2-20x-17=-53

reorder like terms x2= 2x       2x=20x-17=-53

collect like terms 2x-20x=-18x           -18x-17=-53

move constant to the right hand side and change its sign   -18x=-53+17

calculate the sum -53+17= -36         -18x=-36

divide both sides by -18  -18x÷-18= x        -36÷-18=2

x=2

7 0
3 years ago
7. In the accompanying diagram of right triangle ABC, altitude BD divides hypotenuse
xxMikexx [17]

Answer:

A.

Step-by-step explanation:

5 0
3 years ago
Can someone please help me
agasfer [191]

Answer:

See below

Step-by-step explanation:

If |x| < |y|   and both are negative the x will be  to the right of y on the number line.  The point x is loser to the zero on the number line. We can illustrate this by supposing x = -3 and y = -6.

|x| = 3 and |y| = 6  and 3 < 6  but -3 on the number line is higher ( to the right) of -6 and closer to the zero.


|-8 1/3| = 8 1/3

|7  2/3|  = 7 2/3

The absolute values of 8 1/3 > than absolute value of 7 2/3.  The point 7 2/3 is closer to the zero on a number line.

The absolute value of F is greater than absolute value of E so E is closer to the zero line than F.


6 0
3 years ago
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